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krok68 [10]
2 years ago
7

Write Your recurrring decimal 0.255555...... as a fraction

Mathematics
2 answers:
ICE Princess25 [194]2 years ago
6 0

Answer:

\frac{23}{90}

Step-by-step explanation:

we require 2 equations with the recurring digit placed after the decimal point.

let x = 0.2555.. ( multiply both sides by 10 and 100 )

10x = 2.555... (1)

100x = 25.555.... (2)

subtract (1) from (2) thus eliminating the recurring digits

90x = 23 ( divide both sides by 90 )

x = \frac{23}{90}

QveST [7]2 years ago
5 0

Answer:

\sf \dfrac{23}{90}

Step-by-step explanation:

  x = 0.25555.....  --------------(I)

Number of non-recurring digits is 1. So, multiply equation (I) by 10.

10x = 2.5555.... --------------(II)

Number of recurring digits is 1. So, multiply equation (II) by 10.

 100x = 25.5555...... (III)

Subtract equation (II) from (III)

     100x = 25.5555........

       10x =    2.5555.......

   <u> -             -                      </u>

         90x = 23

             x = 23/90

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