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Pavel [41]
3 years ago
12

When evaluating the expression 3 x (3 + 12/3) - 4, Ryan began with 3 + 12. What was Ryan's mistake?

Mathematics
2 answers:
Airida [17]3 years ago
6 0

Answer:

He didn't follow the pemdas rule<u> (see explanation)</u>

Step-by-step explanation:

Rayan's mistake is that he didn't follow the pemdas rule, which states that you start with wat is inside parentheses first, then exponents then multiplication and division(from left to right) and then adding and  subtracting (from left to right).

KIM [24]3 years ago
3 0

Answer:

He has to divide 12/3 first

Step-by-step explanation:

it’s like pemdas you have to do that first then you go on to added the 3+ whatever 12/3 is

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What is the solution to the following system of equations?<br><br> x+y=5<br> x-y=1<br> step by step
Andreas93 [3]
x+y=5
-x -x

Equals:

y=-x+5

Now you have:

y=-x+5
x-y=1

Insert -x+5 into y

x-x+5=1

Combine like terms

2x+5=1

Subtract 5.

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Divide 2.

Answer: x=-2

8 0
3 years ago
A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
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Advocard [28]

Answer:

Step-by-step explanation:

try https://www.mathpapa.com/calc.html?q=y%3D2x+1 for faster answers next time

5 0
3 years ago
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Airida [17]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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il63 [147K]
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7 0
3 years ago
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