(6(x^2-1))*((6x-1)/(6(x+1))
(6((x+1)(x-1)))((6x-1)/(6(x+1))
(6(x-1))*(6x-1)/(6)
(x-1)(6x-1)
6x^2-x-6x+1
6x^2-7x+1
p would be the number of parking meters that dont accpet nickels and the p^ would be the number of parking meters that accpet nickels
Answer: Six places to the right
Step-by-step explanation:
For this exercise it is important to remember that. by definition, the exponent of a number indicates the number of times you must use the same factor to multiply.
Given:

"b" is the base and "n" is the exponent.
In this case, you have the following multiplication provided in the exercise:

Notice that the base 10 has an exponent 6. This indicates the following:

By definition, moving the decimal point 6 places to the right (because there are six zeros), is the same as multiplying the decimal number 34.05 by 1,000,000.
Therefore, based on the explained, when you move the decimal point six places to the right, you get the following product.

Answer: Exponential decay model:
y
=
x
(
1
−
r
)
t
, half life of tablet is about
2
hours and after
t
=
3
hours , remaining drug on patient's system is
42.875
mg.
Step-by-step explanation: Initial drug
x
=
125
mg ; rate of decay
r
=
30
100
=
0.3
gm/hour
Exponential model:
y
=
x
(
1
−
r
)
t
=
125
(
1
−
0.3
)
t
=
125
⋅
0.7
t
Half life:
y
=
125
2
=
62.5
mg
∴
62.5
=
125
⋅
0.7
t
or
0.7
t
=
1
2
. Taking logarithm on both sides we get ,
t
log
(
0.7
)
=
log
(
0.5
)
∴
t
=
log
(
0.5
)
log
(
0.7
)
≈
1.94
(
2
d
p
)
hour
The half life of tablet is about
2
hours.
After
t
=
3
hours , remaining drug on patient's system is
y
=
125
⋅
0.7
t
=
125
⋅
0.7
3
=
42.875
mg [Ans]