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k0ka [10]
2 years ago
6

Which statements accurately describe how to determine the y-intercept and the slope from the graph below? On a coordinate plane,

a line goes through points (0, negative 6) and (3, 0). To find the y-intercept, begin at the origin and move horizontally to the graphed line. To find the slope, use two ordered pairs on the line and substitute into the equation m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction. To find the y-intercept, begin at the origin and move horizontally to the graphed line. To find the slope, use two ordered pairs on the line and substitute into the equation m = StartFraction x 2 minus x 1 Over y 2 minus y 1 EndFraction. To find the y-intercept, begin at the origin and move vertically to the graphed line. To find the slope, use two ordered pairs on the line and substitute into the equation m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction. To find the y-intercept, begin at the origin and move vertically to the graphed line. To find the slope, use two ordered pairs on the line and substitute into the equation m = StartFraction x 2 minus x 1 Over y 2 minus y 1 EndFraction.

Mathematics
1 answer:
allochka39001 [22]2 years ago
3 0

Answer:

To find the y-intercept, begin at the origin and move vertically to the graphed line. To find the slope, use two ordered pairs on the line and substitute into the equation m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction.

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Mario fille a hummingbird feeder with 3/4 cup of sugar water on Friday .Monday , Mario sees that 1/8 of sugar water is left .how
tino4ka555 [31]

\frac{5}{8} of total sugar was drink by humming bird

<h3><u>Solution:</u></h3>

Given that,

When the Mario kept the humming feeder on Friday it had \frac{3}{4} cup of sugar water

When he sees on Monday, it had only \frac{1}{8} of sugar water

So, this means the water is consumed by the humming bird will be the difference of the two values:-

\text { Sugar water consumed }=\frac{3}{4}-\frac{1}{8}

On solving we get,

=\frac{3}{4}-\frac{1}{8}=\frac{24-4}{32}=\frac{20}{32}

=\frac{5}{8}

Hence, the amount of sugar water consumed is \frac{5}{8} of total sugar at the starting

5 0
4 years ago
A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
chubhunter [2.5K]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

8 0
3 years ago
Can someone verify if this is correct
Anestetic [448]

Answer:

No.

Step-by-step explanation:

Your line should start at the point (0,-4) and move up 3 and over 1. The next point should be at (1,-1).

8 0
3 years ago
Read 2 more answers
What is 196.7 16 in simplest form?
Lilit [14]
70/196 is 5/14
GCD OF 70 and 196 is 14
70 divided by 14
196 divided by 14
Reduced fraction: 5/14
3 0
3 years ago
Over the summer, for every 13 okra seeds Dana planted, 8 grew into plants. If he planted 130 okra seeds, how many grew into plan
schepotkina [342]
The answer will be 26 beaus if you subtract 13 by 8 that equals 5 and if u divide that number by 130 it will equal 26
6 0
4 years ago
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