Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer:
<h2>
x²+7x-2 = 0</h2>
Step-by-step explanation:
The general form of a quadratic equation with roots a and b is expressed as shown;
x²-(sum of root) x + (product of roots) = 0
x² - (a+b)x + ab = 0 ... 1
Given the sum of roots a+b = -7
Product of roots ab = -2
Substituting this values in equation 1 above wil give;
x²-(-7)x+(-2) = 0
x²+7x-2 = 0
The resulting quadratic polynomial is x²+7x-2 = 0
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Answer:
see explanation
Step-by-step explanation:
Given that Bilal is age y and his mother is 25 years older, then
a. Bilal's mothers age is y + 25
b. the sum of their ages = y + y + 25 = 2y + 25
c. Mother is y + 25 = 12 + 25 = 37 years
