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bija089 [108]
2 years ago
8

Cual es el coeficiente de variacion de los resultados de 30,60,90,45?

Mathematics
1 answer:
alexdok [17]2 years ago
8 0

based on the given results, the coefficient of variation can be found to be 45.54.

<h3>what is the coefficient of variation?</h3>

first, find the mean:
= (30 + 60 + 90 + 45) / 4

= 56.25

find the standard deviation using a spreadsheet:

= 25.61737691

the coefficient of variation is therefore:

= standard deviation / mean x 100

= 25.61737691 / 56.25 x 100

= 45.54

find out more on the coefficient of variation at brainly.com/question/13293164.

#SPJ1

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a photograph has a perimeter of 24 in the difference between the photographs Lane and the width is 2 inches. find the length and
DaniilM [7]

L-w=5

L=w+5

P=2*(L+w)=24

L+w=24/2

L+w=12

w+5+w=12

2w+5=12

2w=12-5

2w=7

w=7/2

w=3.5

L=2+3.5

L=5.5

8 0
4 years ago
What is the value of x
sladkih [1.3K]
X = 1/2 (150 - 60) = 45°

Answer: 45°
8 0
4 years ago
(FOR K-12 STUDENTS) Keith correctly determined the area of this parallelogram by adding the areas of the triangles and rectangle
Gemiola [76]

The area of the parallelogram using area of rectangle and area of two triangles is 84 m²

<h3>How to find area of a parallelogram</h3>

  • Area of a rectangle = length × width

= 8m × 7m

= 56 m²

  • Area of each triangle = 1/2 × base × height

= 1/2 × 4m × 7m

= 1/2 × 28

= 14m²

  • Total area of triangles = 2(14 m²)

= 28 m²

  • Area of parallelogram = area of rectangle + area of two triangles

= 56 m² + 28 m²

= 84 m²

Learn more about area of triangle:

brainly.com/question/21735282

4 0
2 years ago
Read 2 more answers
Area of hexagon please help
podryga [215]

\frac{ 3\sqrt{3} }{2}  \times a {}^{2}  \\  \\   \frac{ \sqrt{27} }{2} \times 7 {}^{2}  \\  \\ \frac{ \sqrt{27} }{2} \times 49 \\  \\  = 127.31cm {}^{2}

<h3>So Option D=127.3cm²</h3>

<h3>Hope This Helps You </h3>

3 0
3 years ago
What equation represents a line that passes through (2,-1/2) and has a slope of 3?
Lunna [17]

Answer:

C. y+1/2=3(x-2)

Hope this helps

7 0
4 years ago
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