What is the answer to this question x=2y+4 y=x-2

The box office manager said about 5,000 people attended the show. Write a number that could be the actual attendance if he corre

IRINA_888 [86]

In the given mathematical value of 5,000 to round off this number to the nearest hundred, we can elaborate the number values using the expanded form to clearly see the order position: 1. 5,000 = thousands
Now we can observe the numerical value of 4,900 as the rounding number which becomes

4900 = 5000
4800 = 5000
4700 = 5000
4600 = 5000
4500 = 5000


7 0

3 years ago

Read 2 more answers

Find the GCF of the given list. x^17 y^3, x^4 y^3, x^5 y^5

trasher [3.6K]

Answer:

the greatest common factor is 1.

Step-by-step explanation:

The factors of 3 are: 1, 3

The factors of 4 are: 1, 2, 4

The factors of 5 are: 1, 5

The factors of 17 are: 1, 17

Then the greatest common factor is 1.

7 0

2 years ago

Tim wants to determine the height, x, of a nearby tree. He stands 35 feet

kodGreya [7K]

Answer:

x ≈ 29.4 ft

Step-by-step explanation:

The model is a right triangle.

Using the tangent ratio

tan40° = $\frac{opposite}{adjacent}$ = $\frac{x}{35}$ ( multiply both sides by 35 )

35 × tan40° = x , then

x ≈ 29.4 ft ( to 1 dec. place )

6 0

2 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .