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Furkat [3]
1 year ago
14

Which statement is true regarding the graphed functions?

Mathematics
1 answer:
MAVERICK [17]1 year ago
7 0
The correct answer is 2+ because it is last in line when dividing
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What is (6.89+14.52)+(-14.52)???
MrRa [10]
The answer is 6.89 because
6.89+14.52=21.41
So 21.41+(-14.52)=6.89
7 0
3 years ago
Please solve. 6(3 + 8) - 4/5
Gre4nikov [31]

G'Day mate! Here's the answer:

53 1/3

1. 6(3 + 6) - 4/5

2. 6 x 3 is 18, and 6 x 8 is 48

3. 18 plus 48 is 66

4. 66 - 4/5 = 266/5

5. 266/5 as mixed number is 53 1/5

3 0
3 years ago
Read 2 more answers
Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e
saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in R^{2}. To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.  

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle

Now, let's calculate each vector length by calculating the norm.

\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0
3 years ago
J1, J2 and J3 are three junctions on a motorway. The distance from J2 to J3 is 8.7 miles. The distance from J1 to J2 is one-thir
leonid [27]

Answer:

11.6 miles

Step-by-step explanation:

Given that:

Distance from J2 to J3 = 8.7 miles

Distance between J1 and J2 = 1/3 of J2 toJ3

Hence, distance between J1 and J2 becomes :

1/3 * 8.7 miles = 2.9 miles

Distance from J1 to J3 equals :

(J1 to J2) + (J2 to J3)

2.9 miles + 8.7 miles

= 11.6 miles

5 0
3 years ago
Pls helppppp 30 minutes left!! If correct I'll give brainliest to who answers correct first.
anygoal [31]

Answer:

it should be 3.) x+2

Step-by-step explanation:

4 0
3 years ago
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