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kumpel [21]
2 years ago
12

Solve the system of equations using elimination x-y=3 2x+2y=50

Mathematics
2 answers:
pishuonlain [190]2 years ago
6 0

Answer:

X=14

Y=11

Step-by-step explanation:

14-11=3

14x2=28

11x2=22

22+28=50

Hope that works :)

kaheart [24]2 years ago
3 0
Answer:
X= 14
Y= 11

Hope this helps bye have a great day :)
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PLZ HELP WITH THIS QUESTION!
Bad White [126]

Answer:

D

Step-by-step explanation:

Given the quadratic

d = - 16t² + 12t ← subtract d from both sides

- 16t² + 12t - d = 0 ← in standard form

with a = - 16, b = 12, c = - d

Use the quadratic formula to solve for t

t = ( - 12 ± \sqrt{12^2-(4(-16)(-d))}) / - 32

 = ( - 12 ± \sqrt{144-64d}) / - 32

 = ( - 12 ± \sqrt{16(9-4d)}) / - 32

 = ( - 12 ± 4\sqrt{9-4d}) / - 32

 = \frac{-12}{-32} ± \frac{4}{-32}\sqrt{9-4d}

 = \frac{3}{8} ± \frac{1}{8}\sqrt{9-4d}

 = \frac{3}{8} ± \frac{\sqrt{9-4d} }{8} → D

8 0
3 years ago
Caleb has 550 candy bars and eats 2 a day. Robert has 850 candy bars and eats 6
Alex17521 [72]

Answer:

B. 550 - 2x > 850 - 6x

Step-by-step explanation:

7 0
2 years ago
Denise rolled a number cube several times. The results are shown.
strojnjashka [21]
4/156 so
2/78 so
1/39 so approx. 2.5641%
5 0
3 years ago
Read 2 more answers
Look at the example problem. Suppose Alana walks 6.6 miles the next day. Complete the steps below to find the number of miles sh
alexandr402 [8]

Answer:

Looking at the example Alana will walk. 15.23 miles in two days

step-by-step explanation:

Looking at the example and using place value system

8.63 + 6.60= 15.23 miles

4 0
3 years ago
two pumps of different sizes, working together, can empty a fuel tank in 3 hours. the larger pump can empty the tank in 4 hours
bonufazy [111]
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour. 


8 0
3 years ago
Read 2 more answers
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