Question

The vendor of a coffee cart mixes coffee beans that cost $9 per pound with coffee beans that cost $5 per pound. How many pounds of each should be used to make a 75-pound blend that sells for $6.00 per pound

Answer 1

Answer:

56.25 pound of the coffee that costs $5 per pound is needed

18.75 pound of the coffee that costs $9 per pound is needed

Step-by-step explanation:

Let the number of pounds be x and y respectively

The total pounds is 75;

So;

x + y. = 75 •••••••(i)

Total cost of first type

9 * x = $9x

Total cost of second type;

5 * y= $5y

75 pound at $6 per pound; total cost of this is;

6 * 75 = $450

Thus;

9x + 5y = 450 ••••••••(ii)

From i, x = 75-y

Put this into ii

9(75-y) + 5y = 450

675 -9y + 5y = 450

4y = 675-450

4y = 225

y = 225/4

y = 56.25

x = 75 - y from i

x = 75-56.25

x = $18.75