The error made by zacharias in solving the quadratic equation 0 = -2x² + 5x - 3 using quadratic formula is; the 2 in the numerator should be –2.
There are four methods of solving quadratic equation. Namely;
0 = -2x² + 5x - 3
x = -b ± √b² - 4ac / 2a
where,
x = -5 ± √5² - 4(-2)(-3) / 2(-2)
= -5 ± √25 - (24) / -2
= -5 ± √1 / -2
= -5/2 ± 1/2
= -5/2 - 1/2 or x = -5/2 + 1/2
= -5-1 / 2 or -5+1/ 2
x = -6/2 or -4/2
x = -3 or -2
Therefore, the solution to the quadratic equation is x = -3 or -2
Learn more about quadratic equation:
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Step-by-step explanation:
0+1 = 1
1/2+1/2= 1
-50 + 51= 1
Parameterize by the vector function
so that the normal vector to is given by
with magnitude
In this case, the normal vector is
with magnitude . The integral of over is then
where is the region in the plane over which is defined. In this case, it's the triangle in the plane which we can capture with and , so that we have
Answer:
x= 7/5
Cos b
1/2[sin(a+b)+sin(a-b)]
1/2[sin a cos b +cos a sin b + sin A cos B - cos A sin B]
1/2[2sin a cos b]
sin a cos b