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2 years ago

Which of the following number sentences is an example of the Distributive Property?

Mathematics

1 answer:

leonid [27]2 years ago

7 0

Answer:

d. 7 × (10 + 9) = (7 × 10) + (7 × 9)

Step-by-step explanation:

The format of writing numbers in distributive property is a(b+c) = (a×b)+(a×c)

We can see that in choice d. 7 × (10 + 9) = (7 × 10) + (7 × 9) it is in correct format of writing numbers in distributive property. Thus, choice d. is correct.

Verification:-

a(b+c) = (a×b)+(a×c)

7 × (10 + 9) = (7 × 10) + (7 × 9)

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Create a square root with at least 3 transformations

Fittoniya [83]

Answer:

Step-by-step explanation:

Start with f(x) = √x.

1) Multiplying this by "c" will either stretch or shrink the graph: stretch, if "c" is > 0; shrink, if 0 < c < 1.

2) Replacing 'x' with 'x - h' will translate the original graph h units to the right, if h is positive;

Replacing 'x' with 'x - h' will translate the original graph h units to the left, if h is negative.

3) Adding k to f(x) = √x will translate the graph upward by k units if k is positive and downward by k units if k is negative.

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2 years ago

Juice: 48 fluid ounces for $2.07; 32 fluid ounces for $1.64

Alla [95]

Answer:

Step-by-step explanation:

Start by changing the dollars into cents.

2.07 dollars = 2.07 * 100 = 207 cents

1.64 dollars = 1.64 * 100 = 164 cents.

How much does 1 ounce cost for each?

207 cents / 48 = 4.3125 cents / oz

164 / 32 = 5.125

The better buy is the 48 fluid oz jar.

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2 years ago

W(1,8),X(7,8),Y(4,5), and Z(1,2) select all methods you can use to prove WYZ is congruent to WYX

marin [14]

The distance between two points (x₁,y1),(x₂,y₂) is d
$d= \sqrt{(x2-x1)^2 + (y2-y1)^2}$

For the given problem we have
W(1,8),X(7,8),Y(4,5), and Z(1,2)

The length of WY = $\sqrt{(4-1)^2 + (5-8)^2}$ = 3√2
The length of WX = $\sqrt{(7-1)^2 + (8-8)^2}$ = 6
The length of WZ = $\sqrt{(1-1)^2 + (2-8)^2}$ = 6
The length of XY = $\sqrt{(4-7)^2 + (5-8)^2}$ = 3√2
The length of ZY = $\sqrt{(1-4)^2 + (2-5)^2}$ = 3√2

∴ WX = WZ ⇒⇒⇒ proved
XY = ZY ⇒⇒⇒ proved
WY = WY ⇒⇒⇒ reflexive property

∴ ΔWYZ is congruent to ΔWYX by SSS method

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2 years ago

Find the derivative of |x|/(x-1)

ki77a [65]

$\bf \cfrac{|x|}{x-1}\iff \cfrac{\sqrt{x^2}}{x-1}\iff \cfrac{(x^2)^{\frac{1}{2}}}{x-1}
\\\\\\
\textit{using the quotient rule}
\\\\\\
\cfrac{dy}{dx}=\cfrac{\frac{1}{2}(x^2)^{-\frac{1}{2}}\cdot 2x(x-1)-(x^2)^{\frac{1}{2}}\cdot 1}{(x-1)^2}$

$\bf \cfrac{dy}{dx}=\cfrac{\frac{x(x-1)-(x^2)^{\frac{1}{2}}}{(x^2)^{\frac{1}{2}}}}{(x-1)^2}\implies \cfrac{dy}{dx}=\cfrac{x(x-1)-(x^2)^{\frac{1}{2}}}{(x^2)^{\frac{1}{2}}(x-1)^2}
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4 0

2 years ago

Write (5y) exponent 2 without exponents

mixer [17]

(5y)^{2}
= 5y*5y = 25y*y

3 0

3 years ago

Read 2 more answers