The sum of the squared deviation scores is s = 20 for a population of n = 5 scores. what is the variance for this population?

White raven [17]

It would be written as:

50+9+0.60+0.09

3 0

2 years ago

Which trigonometric ratio is correct for triangle DEF? (Hint: Use Pythagorean Theorem first) A.) Sin(D)= 24/7 B.) Tan(D)= 24/25

Tanya [424]

Answer:

Cos E= 24/25

Step-by-step explanation:

Length of hypotenuse: 7^2+24^2=625. 625 square root=25

Thus, DE is 25.

Sin D= 24/25, so that is false.

Tan D= 24/7, so that is false.

Cos E= 24/25, so that is true

Sin E= 7/25, so that is false.

4 0

3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is: