Answer:
Yes
Step-by-step explanation:
I've done this before.
Answer:
<u>Step 1: Determine why circle 1 is similar to circle 2</u>
The reason why circle 1 is similar to circle 2 is that they both expand at the same rate. While x grows larger, both circle 1 and circle 2 grow at a proportional rate. Circle 2 grows is 5 times bigger than circle 1 given any value 5.
<u>When x = 3:</u> circle 1 = 6 and circle 2 = 30
<u>When x = 10:</u> circle 1 = 20 and circle 2 = 100
Answer:
D. (-1, 3/2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define System</u>
4x + 2y = -1
3x + 4y = 3
<u>Step 2: Rewrite System</u>
4x + 2y = -1
- [Multiplication Property of Equality] Multiply -2 on both sides: -2(4x + 2y) = 2
- [Distributive Property] Distribute -2 on both sides: -8x - 4y = 2
<u>Step 3: Redefine Systems</u>
-8x - 4y = 2
3x + 4y = 3
<u>Step 4: Solve for </u><em><u>x</u></em>
- Combine equations: -5x = 5
- [Division Property of Equality] Divide -5 on both sides: x = -1
<u>Step 5: Solve for </u><em><u>y</u></em>
- Substitute in <em>x</em> [Original Equation]: 3(-1) + 4y = 3
- Multiply: -3 + 4y = 3
- [Addition Property of Equality] Add 3 on both sides: 4y = 6
- [Division Property of Equality] Divide 4 on both sides: y = 3/2
2/3 is equal to 4/6 When multiplied by 2/2. You can do this because 2/2 is still equal to one so it doesn’t change the value, just how it looks
Answer:
p-value (0.0208) is less than alpha = 0.05 reject H0.
Step-by-step explanation:
we have the following data:
sample size = n = 75
x, the number to evaluate is 45
the sample proportion would be: x / n = 45/75
p * = 0.6
Now, the null and alternative hypotheses are:
H0: P = 0.72
Ha: P no 72
two tailed test
statistic tes = z = (p * - p) / [(p * (1-p) / n)] ^ (1/2)
replacing we have:
z = (0.6 - 0.72) / [(0.72 * (1-0.72) / 75)] ^ (1/2)
z = -2.31
p-vaule = 2 * p (z <-2.31)
using z table, we get:
p-vaule = 2 * (0.0104)
p-vaule = 0.0208
Therefore, p-value (0.0208) is less than alpha = 0.05 reject H0.
