Answer:
<em>10j + v - 20</em>
<em>Step-by-step explanation:</em>
<em>~Thank you have a nice day/night~</em>
<em>~Evelyn </em>
The number of combinations of 2 health care providers of different types possible are 47.
<u>Explanation:</u>
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Doctors = 4
Dentists = 3
Nurses = 5
combinations of two different health care providers = ?
Combination would be = ⁴C₁ X ³C₁ + ³C₁ X ⁵C₁ + ⁴C₁ X ⁵C₁
ⁿCₐ = n! / ( n - a )! X a!
So on calculating the combination we get,
= 4 X 3 + 3 X 5 + 4 X 5
= 12 + 15 + 20
= 47
Therefore, the number of combinations of 2 health care providers of different types possible are 47.
Answer:
Enjoy, Glad i could help
Step-by-step explanation:
Answer:
62.28divided by 0.75 = 83.04
Step-by-step explanation:
PEMDAS - Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.
The answer is either 257,600 or 257,700. I think you need to round up to 127,700.