Let's actually find the line of best fit...
m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)
m=(11*836-130*55)/(11*385-3025)
m=2046/1210
m=93/55
b=(Σy-93Σx/55)/n
b=(55Σy-93Σx)/(55n)
b=(7150-5115)/(55*11)
b=185/55, so the line of best fit is:
y=(93x+185)/55
A) The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.
Which means that those who do not practice at all will win about 3.36 times
B) y(13)=(93x+185)/55
y(13)≈25.34
So after 13 months of practice one would expect to win about 25.34 times.
The probability of all possible outcomes is always 1, meaning 100%.
In this case the probability of rolling a 1,2,3,4,5, or 6 is:
1/6+1/6+1/6+1/6+1/6+1/6
6(1/6)
6/6
1
Not quite sure, can’t see the picture
now, the one below that, which is equivalent to that? well, just look above it
