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andreev551 [17]
3 years ago
7

If α and β are the zeroes of the polynomial 2x2 + 3x – 7, then find a polynomial whose zeroes are and .

Mathematics
1 answer:
Drupady [299]3 years ago
5 0

Answer:

\frac{-\sqrt{65} - 3 }{4}, \frac{\sqrt{65} + 3}{4}

Step-by-step explanation:

Since we cannot factor the expression, we must use quadratic formula: x = \frac{-b +/-\sqrt{b^2 - 4ac} }{2a}

Plug in <em>a</em> for 2, <em>b</em> for 3, and <em>c</em> for -7 and you should find your roots.

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The slope of the line containing the points (-5, 3) and (-2, 1) is
lianna [129]

Answer:

A.-2/3

Step-by-step explanation:

formula of gradient

dy/dx=y2-y2/x2-x1

1-3/-2-(-5)

=-2/3.

5 0
3 years ago
HELPPPP ASSAP WITH THIS QUESTION
arsen [322]
M is always positive is not true.

Hope this helps!
6 0
3 years ago
(9x+13)^2=49<br> Solve the quadratic equation given below.
Varvara68 [4.7K]

Answer:

x=(-2/3)

Step-by-step explanation:

(9x+13)^2=49

√(9x+13)^2=√49

9x+13=7

9x+13-13=7-13

9x=-6

9x÷9=-6/9

x=-6/9

-6/9=-2/3

3 0
3 years ago
The sum of 3 consecutive odd numbers is 183. what is the second number in this sequence?
Juliette [100K]
Let, the numbers are: x, (x+2), (x+4)
Now, x+x+2+x+4 = 183
3x + 6 = 183
3x = 177
x = 59

So, second number would be: (x+2) = (59+2) = 61

In short, Your Final answer would be 61

Hope this helps!
4 0
3 years ago
Determine whether the three segment lengths will produce a triangle. Type yes or no in the space provided.
tresset_1 [31]

Answer:

20 , 20 , 30 will produce a triangle

Step-by-step explanation:

* Lets study how to know if the lengths of the three segments

 can formed a triangle

- It is a fact that in any triangle the sum of the smallest two sides

 must be greater than the largest side

- Lets study some examples

# If the lengths of the three segments are 5 , 6 , 7

∵ 5 and 6 are the smallest

∴ 5 + 6 = 11

∵ 11 > 7 ⇒ the sum greater than the 3rd side

∴ 5 , 6 , 7 can formed a triangle

# If the lengths of the three segments are 5 , 7 , 12

∵ 5 and 7 are the smallest

∴ 5 + 7 = 12

∵ 12 = 12 ⇒ the sum equal the 3rd side

∴ 5 , 7 , 12 can not formed a triangle

# If the lengths of the three segments are 10 , 12 , 24

∵ 10 and 12 are the smallest

∴ 10 + 12 = 22

∵ 22 < 24 ⇒ the sum less than the 3rd side

∴ 10 , 12 , 24 can not formed a triangle

* Now lets solve the problem

∵ The length of the three segments are 20 , 20 , 30

∵ 20 and 20 are the smallest

∴ 20 + 20 = 40

∵ 40 > 30 ⇒ the sum greater than the 3rd side

∴ 20 , 20 , 30 will produce a triangle

5 0
2 years ago
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