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2 years ago

If α and β are the zeroes of the polynomial 2x2 + 3x – 7, then find a polynomial whose zeroes are and .

Mathematics

1 answer:

Drupady [299]2 years ago

5 0

Answer:

$\frac{-\sqrt{65} - 3 }{4}, \frac{\sqrt{65} + 3}{4}$

Step-by-step explanation:

Since we cannot factor the expression, we must use quadratic formula: $x = \frac{-b +/-\sqrt{b^2 - 4ac} }{2a}$

Plug in a for 2, b for 3, and c for -7 and you should find your roots.

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In the diagram below, P is circumscribed about quadrilateral ABCD. What is the value of x?

alexira [117]

We know that
In any quadrilateral where the vertices are on the circumference of a circle, the opposite angles add up to $180$ degrees.

So,
in this problem
$(x+20) + 110 = 180 \\ x+130=180 \\ x=180-130 \\ x=50degrees$

therefore

the answer is
$x=50degrees$

7 0

3 years ago

Read 2 more answers

Parallelogram TUVW is graphed on a coordinate plane with vertices at T (3, 4), V (-10,-2), V(-6,5),

zalisa [80]

The coordinates of the dilated vertex V' is (-6p, 5p)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.

Dilation is the increase or decrease in the size of a figure. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).

The Parallelogram TUVW has vertices at T(3, 4), U(-10,-2), V(-6,5) and W (7,11). If it is dilated by a scale factor p with the origin, the new point is at:

T'(3p, 4p), U'(-10p, -2p), V'(-6p, 5p) and W'(7p, 11p)

Find out more on dilation at:brainly.com/question/10253650

3 0

2 years ago

Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

6 0

3 years ago

List all partitions of the set. (a) (1,2) (b) [a, b,c)

Alchen [17]

Answer: Hello mate!

The partition of a set is defined as a partition of the set into a nonempty subset, where the set itself is a subset of himself, then the set is a partition of himself.

a) in this we have a set of two objects; A = (1,2) the partitions of this set are: (∅), (1), (2) and (1,2). Where (∅) is the null set.

b) Now we have a set of three objects; B = (a,b,c) the partitions of this set are: (∅), (a), (b), (c), (a,b), (a,c), (b,c), (a,b,c)

3 0

2 years ago

Y=-6x-2, y=-6x-2 how many solutions are in it

GuDViN [60]

Answer:

Infinite

Step-by-step explanation:

I hope this helps, if it doesn't then just message me and ill be more than happy to help :)

8 0

1 year ago