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aleksley [76]
3 years ago
12

Can some one plz tell me the answer

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
6 0
1/tan(42)*18=20
Hope it helps
koban [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Step-by-step explanation:

Hello there!!

You can find it through simple way of ratio of sin or also by using cosine rule.

Lets do it simply as i can see your just 1st pic not second one so, i will answer you according to it.

so, here in question a Right angled triangle is given, with one angle 31° and one side 15 cm.

let's take sin angle as sin 31°.

so, p=h

h=15

We dont need base (b) here.

As we know that, thesin in ratio angle is

sin thita = p/h

or, sin 31°=h/15

or, 0.515038×15=h (using calculator sin 31°=0.515038.)

Therefore, the answer is 7.722557cm or 8cm.(as 7>5 and rounding off it we get 8).

Hope it helps...

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Let a be a rational number and b be an irrational number. Which of the following are true statements?(there is more than 1 answe
kramer
<span>A.) the sum of a and b is never rational.
This is a true statement. Since an irrational umber has a decimal part that is infinite and non-periodical, when you add a rational number to an irrational number, the result will have the same infinite non periodical decimal part, so the new number will be irrational as well.

</span><span>B.) The product of a and b is rational
This one is false. Zero is a rational number, and when you multiply an irrational number by zero, the result is always zero.

</span><span>C.) b^2 is sometimes rational
This one is true. When you square an irrational number that comes from a square root like </span>\sqrt{2}, you will end with a rational number: ( \sqrt{2} )^{2}=2, but, if you square rationals from different roots than square root like \sqrt[3]{2}, you will end with an irrational number: \sqrt[3]{2^{2} } = \sqrt[3]{2}. 

<span>D.) a^2 is always rational
This one is false. If you square a rational number, you will always end with another rational number.

</span><span>E.) square root of a is never rational
</span>This one is false. The square root of perfect squares are always rational numbers: \sqrt{64} =8, \sqrt{16} =4,...

F.) square root of b is never rational
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4 0
3 years ago
Hiiii! Can someone help me plsss
Grace [21]

Answer: 3/2

Step-by-step explanation:

Slope is the coefficient in front of x, slope tells you how you move when plotting on a graph.

6 0
2 years ago
How to write parallel and perpindicular lines
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Answer:

Parallel lines are straight lines that don't ever touch. Think of a railroad track.

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7 0
3 years ago
Hi does any one know how to solve this y=__x+__
Karolina [17]

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Step-by-step explanation:

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7 0
3 years ago
Which systems of equations intersect at point A in this graph?
abruzzese [7]

Answer:

The point of intersection of the system of equations is:

(x, y) =  (-2, 1)

The correct system of equations intersect at point A in this graph will be:

\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}

Thus, the second option is correct.

Step-by-step explanation:

Given the point

  • A (-2, 1)

Let us check the system of equations to determine whether it intersect at point A in this graph.

Given the system of equations

\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}

Arrange equation variable for elimination

\begin{bmatrix}y-4x=9\\ y+3x=-5\end{bmatrix}

so

y+3x=-5

-

\underline{y-4x=9}

7x=-14

so the system of equations becomes

\begin{bmatrix}y-4x=9\\ 7x=-14\end{bmatrix}

Solve 7x = -14 for x

7x=-14

Divide both sides by 7

\frac{7x}{7}=\frac{-14}{7}

Simplify

x = -2

For y - 4x = 9 plug in x = 2

y-4\left(-2\right)=9

y+4\cdot \:2=9

y+8=9

Subtract 8 from both sides

y+8-8=9-8

Simplify

y = 1

Thus, the solution to the system of equations is:

(x, y) = (-2, 1)

From the attached graph, it is also clear that the system of equations intersects at point x = -2, and y = 1.

In other words, the point of intersection of the system of equations is:

(x, y) =  (-2, 1)

Therefore, the correct system of equations intersect at point A in this graph will be:

\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}

Thus, the second option is correct.

3 0
3 years ago
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