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aleksley [76]
3 years ago
12

Can some one plz tell me the answer

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
6 0
1/tan(42)*18=20
Hope it helps
koban [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Step-by-step explanation:

Hello there!!

You can find it through simple way of ratio of sin or also by using cosine rule.

Lets do it simply as i can see your just 1st pic not second one so, i will answer you according to it.

so, here in question a Right angled triangle is given, with one angle 31° and one side 15 cm.

let's take sin angle as sin 31°.

so, p=h

h=15

We dont need base (b) here.

As we know that, thesin in ratio angle is

sin thita = p/h

or, sin 31°=h/15

or, 0.515038×15=h (using calculator sin 31°=0.515038.)

Therefore, the answer is 7.722557cm or 8cm.(as 7>5 and rounding off it we get 8).

Hope it helps...

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Answer:

volume of cube=441cm³

l³=441cm³

l=

\sqrt[3]{441}

length=7.6cm

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3 years ago
PLEASE HELP FOR 48 POINTS PLEASE!<br><br><br><br> show/explain your answer and work
pentagon [3]

Answer:

c  This is the direct variation

Step-by-step explanation:

The equation for direct variation is y= kx

Solving this for k

y/x =k

So y/x must be a constant

a.  9/3 =3

2/7 does not =3  so this is not a direct variation


b 1/2 = .5

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c.  27/9 =3

18/6 =3

9/3 =3

This is a direct variation with a constant of 3


d 5/-7 = -5/7

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4 0
3 years ago
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What is the exact distance from (-5,1) to (3,0).
Ilya [14]

Answer:

The distance between the two points is \sqrt{65} \ \text{units}.

Step-by-step explanation:

In order to find the distance between two coordinate pairs, we can use the distance formula:

\displaystyle \bullet  \ \ \ d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Our coordinate pairs need to be labeled accordingly, so we can use this naming system:

\bullet  \ \ \ (x_1, y_1), (x_2, y_2)

This assigns a name to our points:

  • x_1 = -5
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Therefore, we can plug these into the formula and solve:

d=\sqrt{(3-(-5))^2+(0-1)^2}\\\\d=\sqrt{(8)^2+(-1)^2}\\\\d=\sqrt{8^2+1^2}\\\\d=\sqrt{64+1}\\\\d=\sqrt{65}

Therefore, the distance between the two points is \sqrt{65} \ \text{units}.

5 0
2 years ago
What do you notice about the table inputs for the graph of √x?
Airida [17]

Answer:

See below

Step-by-step explanation:

When we talk about the function f(x)=\sqrt{x}, the domain and codomain are generally defaulted to be subsets of the Real set. Once $f:[0,\infty)\to [0,\infty)$ and  $f\subseteq [0,\infty)\times [0,\infty)$ such that $(x,y_1)\in f\wedge(x,y_2)\in f \Rightarrow y_1=y_2$  for $f(x)=\sqrt x$. Therefore,

\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]

\[x \mapsto \sqrt{x}\]

But this table just shows the perfect square solutions.

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