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g100num [7]
3 years ago
11

Need help ASAP Geometry

Mathematics
1 answer:
nadya68 [22]3 years ago
8 0

Answer:

Step-by-step explanation:

5x-1 is twice the bisector angle 4x-17 so

5x-1=2(4x-17)

5x-1=8x-34

-3x=-33

x=11, abc=5x-1

5(11)-1=54

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Plsssssssss help me in this i need it asap ill give brainly
egoroff_w [7]

Answer:

16

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1
charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t   (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ \frac{dx}{dt} = -\sin t

  \frac{dy}{dt} = 2 \cos t

  \frac{dz}{dt} = \sin t-2cos t

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}

=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)

Now evaluating the integral using calculator,

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t) = 13.5191




8 0
3 years ago
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nydimaria [60]
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Scale factor of 3
3 0
3 years ago
What is the answer???
Pavel [41]

Answer:

I cant see the whole thing

6 0
3 years ago
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