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2 years ago

13

Please solve this question asap

1 answer:

disa [49]2 years ago

3 0

Step-by-step explanation:

$y = \sqrt{4x + 6}$

${y}^{2} = 4x + 6$

${y}^{2} - 6 = 4x$

$\frac{1}{4} ( {y}^{2} - 6) = x$

Swap x and y

$\frac{ {x}^{2} - 6 }{4} = y$

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Given a cylinder with a radius of 5cm and a height of 8 cm, find the volume of the cylinder. Use 3.14 for T.

Radda [10]

Answer: V=628cm³

Step-by-step explanation:

V=(3.14)r²h

V=(3.14)(5²)(8)

V=628cm²

Hope this helps! Have a great night!

6 0

3 years ago

Please help me..please

myrzilka [38]

Why are you asking me for help

6 0

3 years ago

Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th

alexandr1967 [171]

I'm guessing the function is

$f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}$

which, split into partial fractions, is equivalent to

$\dfrac1{x-6}-\dfrac1{x+2}$

Recall that for $|x|$ we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

With some rearranging, we find

$\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n$

valid for $\left|\dfrac x6\right|$ , or $|x|$ , and

$\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

valid for $\left|-\dfrac x2\right|$ , or $|x|$ .

So we have

$f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

$f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)$

$f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n$

Taken together, the power series for $f(x)$ can only converge for $|x|$ , or $-2$ .

6 0

3 years ago

What is the answer to this?

MrMuchimi

The answer is 12x+10

6 0

3 years ago

Find the 20th term of the geometric sequence when A1=2 and r=2

labwork [276]

A_n= a₁ rⁿ⁻¹

a₁ is the first term

r= common ratio

a_n=2(2)²⁰⁻¹= 1048576

8 0

3 years ago