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Tatiana [17]
2 years ago
13

Please solve this question asap

Mathematics
1 answer:
disa [49]2 years ago
3 0

Step-by-step explanation:

y =  \sqrt{4x + 6}

{y}^{2}  = 4x + 6

{y}^{2}  - 6 = 4x

\frac{1}{4} ( {y}^{2}  - 6) = x

Swap x and y

\frac{ {x}^{2} - 6 }{4}  = y

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HELP<br> If you don’t know it then please don’t answer.
vovangra [49]

the answer is 4.8. Your welcome

3 0
3 years ago
If f (x) = 5x + 4 then for what value of x will f(x) equal -11?​
uysha [10]

Answer:

-3

Step-by-step explanation:

3 0
3 years ago
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Determine the intercepts of the line.<br> 8x-5y=-11
vodka [1.7K]

Answer:

if you're talking about slope intercept then

y= 8/5x + 11/5

3 0
2 years ago
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What’s the domain and range of this graph?
avanturin [10]

Given:

The graph of a downward parabola.

To find:

The domain and range of the graph.

Solution:

Domain is the set of x-values or input values and range is the set of y-values or output values.

The graph represents a downward parabola and domain of a downward parabola is always the set of real numbers because they are defined for all real values of x.

Domain = R

Domain = (-∞,∞)

The maximum point of a downward parabola is the vertex. The range of the downward parabola is always the set of all real number which are less than or equal to the y-coordinate of the vertex.

From the graph it is clear that the vertex of the parabola is at point (5,-4). So, value of function cannot be greater than -4.

Range = All real numbers less than or equal to -4.

Range =  (-∞,-4]

Therefore, the domain of the graph is (-∞,∞) and the range of the graph is (-∞,-4].

3 0
2 years ago
Find the amplitude and the equation of the midline of the periodic function.
Masja [62]

Answer:

Option B. Amplitude =3 midline is y =2.

Step-by-step explanation:

In the graph attached we have to find the amplitude and midline of the periodic function.

Amplitude of the periodic function = (Distance between two extreme points on y asxis)/2

=  (5-(-1))/2 = (5+1)/2 =6/2 =3.

Since amplitude of this function is 3 and by definition amplitude of any periodic function is the distance between the midline and the extreme point of wave on one side.

Therefore midline of the wave function is y=2 from which measurement of the amplitude is 3.

6 0
3 years ago
Read 2 more answers
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