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2 years ago

Which is the only state that uses to calculate its area

Mathematics

2 answers:

ICE Princess25 [194]2 years ago

8 0

A trapezoid sound correct but going to jail is fun

Tresset [83]2 years ago

3 0

Answer:

The answer is circle.

Step-by-step explanation:

For all the rest of the shapes, we use certain base x height formulas. Square uses base x height along with parallelograms and trapezoids. For a triangle, we use $\frac{base x height}{2}$ . Though, for a circle, we use the formula $\pi r^{2}$ where r= radius.

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The revenue, in dollars, of a company that manufactures televisions can be modeled by the polynomial 3x²+180x . The cost, in dol

tresset_1 [31]

We use the profit concept, and doing this, it is found that if 150 televisions are sold, the profit is $50,700.

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Profit is given by revenue subtracted by cost.

In this question:

Revenue: $R(x) = 3x^2 + 180x$
Cost: $C(x) = 3x^2 - 160x + 300$

Thus, the profit of selling x televisions is:

$P(x) = R(x) - C(x)$

$P(x) = 3x^2 + 180x - (3x^2 - 160x + 300)$

$P(x) = 3x^2 + 180x - 3x^2 + 160x - 300$

$P(x) = 340x - 300$

-------------------------------------------

For 150 televisions, we have P(150), so:

$P(150) = 340(150) - 300 = 50700$

If 150 televisions are sold, the profit is $50,700.

A similar question is given at brainly.com/question/14469903

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3 years ago

What is the value of x?

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4 years ago

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A family has a day of 5 activities planned: shopping, picnic, hiking, swimming and movie. To make it more adventurous they decid

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The answer is E i just took the test

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3 years ago

Match the circle equations in general form with their corresponding equations in standard form. Not all will be used.

Xelga [282]

The standard form of the equation of a circumference is given by the following expression:

 $(x-h)^{2}+(y-k)^{2}=r^{2} \\ \\ where \ (h, k) \ is \ the \ center \ of \ the \ circumference \ and \ r \ the \ radius$

On the other hand, the general form is given as follows:

 $x^{2}+y^{2}+Dx+Ey+F=0 \\ \\ where: \\ D=-2h, \ E=-2k, \ F=h^{2}+k^{2}-r^{2}$ 

In this way, we can order the mentioned equations as follows:

Equations in Standard Form:

 $\bold{a)} \ (x-6)^{2}+(y-4)^{2}=56 \\ \bold{b)} \ (x-2)^{2} + (y+6)^{2}=60 \\ \bold{c)} \ (x+2)^{2}+(y+3)^{2}=18 \\ \bold{d)} \ (x+1)^{2}+(y-6)^{2}=46$

Equations in General Form:

$\bold{1)} \ x^{2}+y^{2}-4x+12y-20=0 \\ \bold{2)} \ x^{2}+y^{2}+6x-8y-10=0 \\ \bold{3)} \ 3x^{2}+3y^{2}+12x+18y-15=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 3, \ the \ equation \ becomes: \\ x^{2}+y^{2}+4x+6y-5=0 \\ \\ \bold{4)} \ 5x^{2}+5y^{2}-10x+20y-30=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 5, \ the \ equation \ becomes: \\ x^{2}+y^{2}-2x+4y-6=0 \\ \\ \bold{5)} \ 2x^{2}+2y^{2}-24x-16y-8=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 2, \ the \ equation \ becomes: \\ x^{2}+y^{2}-12x-8y-4=0$

$\bold{6)} \ x^{2}+y^{2}+2x-12y$

So let's match each equation:

$\bold{From \ a)} \\ \\ (h,k)=(6,4),\ r=2\sqrt{14} \\ D=-12, \ E=-8 \\ F=-4$

Then, its general form is:

$x^{2}+y^{2}-12x-8y-4=0$

First. a) matches 5) 

$\bold{From \ b)} \\ \\ (h,k)=(2,-6),\ r=2\sqrt{15} \\ D=-4, \ E=12 \\ F=-20$

Then, its general form is:

$x^{2}+y^{2}-4x+12y-20=0$

Second. b) matches 1) 

$\bold{From \ c)} \\ \\ (h,k)=(-2,-3),\ r=3\sqrt{2} \\ D=4, \ E=6 \\ F=-5$

Then, its general form is:

$x^{2}+y^{2}+4x+6y-5=0$

Third. c) matches 3)

$\bold{From \ d)} \\ \\ (h,k)=(-1,6),\ r=\sqrt{46} \\ D=2, \ E=-12, \ F=-9$

Then, its general form is: $x^{2}+y^{2}+2x-12y-9=0$

Fourth. d) matches 6)

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The correct answer is 525seats in the civic theatre.

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3 years ago