All categories

2 years ago

A $ 240 suit is maker down by 20% find the sale price

Mathematics

1 answer:

Annette [7]2 years ago

4 0

Answer:

192

Step-by-step explanation:

You might be interested in

Trisha drew a blueprint of her bedroom, shown below. Denoted by a 4 on the blueprint, her television stand's blueprint dimension

wolverine [178]

From the blue print , the dimensions of the television stand is 1 in x 2 in. so the actual dimension of the trisha's television stand can be calculated:
w = 1 in ( 2 ft / 1 in )
w = 2 ft

l = 2 in ( 2 ft / 1 in )
l = 4 ft

so the actual dimensions of the television stand is 2 ft x 4 ft

5 0

2 years ago

Read 2 more answers

How many millimeters are equal to one kilometer. Show your work

Dafna11 [192]

Answer:

1,000,000

Step-by-step explanation:

1mm=1e-6km

10mm=1e-5km

100mm=1e-4km

1000mm=000.1km

10000mm=0.01km

100000mm=0.1km

500000mm=0.5km

1000000mm=1km

7 0

2 years ago

Appreciate it if u answer the question thx

Lena [83]

Answer:

100

dividing

Step-by-step explanation:

8 0

2 years ago

Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u

soldier1979 [14.2K]

$x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }$

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

$p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}$

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

$\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}$

$\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}$

$\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}$

Therefore:

$\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]$

Recall that at t=25, $p(25)=\dfrac { 5800 } {13} \approx 446.15$

Therefore:

$\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009$

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0

2 years ago

What is the answer for p? I keep getting 2.571428571 but that not the answer and I’ve tried to round it and still not the correc

DENIUS [597]

Answer:

2.15

Step-by-step explanation:

3 0

2 years ago