A lake near the Arctic Circle is covered by a 2-meter-thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a constant rate. After 3 weeks, the sheet is only 1.25 meters thick. Let y represent the ice sheet's thickness ( in meters) after x weeks. Complete the equation for the relationship between the thickness and number of weeks.
Answer:
y = 2 - 0.25x
Step-by-step explanation:
From the question, the initial thickness of the ice sheet = 2 meters,
After 3 weeks, the thickness of ice sheet reduced to 1.25 meters
Hence, the difference in the thickness in 3 weeks is calculated as:
2m - 1.25m = 0.75m
The amount of changes that occurred in 3 weeks is given as:
= 0.75/3 = 0.25 meters,
We are told that, the ice is melting with the constant rate.
Therefore, the equation for the relationship between the thickness and number of weeks is given as:
y = 2 - 0.25x
Answer:
There are 25 students in the class.
Step-by-step explanation:
In order to find the number of students in the class, you can add the number of data points together. Because the name of each person will only be recorded once and only to one data value, that means by adding the total number of data points collected, you can find out the number of students in the sixth-grade class. There are three data points on 3, two data points on 4, five data points on 5, eight data points on 6, two data points on 7, one data point on 8, and four data points on 9, this means the total number of students will be 3 + 2 + 5 + 8 + 2 + 1 + 4 = 25 students, so this will be your answer.
Answer:
It would take 4 minutes.
Step-by-step explanation:
Step 1: divide 63 by 3 to get how many hotdogs the champion can eat in a minute which equals 21
Step 2: Divide 84 by 21 to get 4 minutes
Start with this formula
Y=mx+b
you will get
Y=2x
Answer:
(3•22g4h5)
Step-by-step explanation:
Step 1: ((3gh2 • 4) • g3) • h3
Step 2: ((3•22gh2) • g3) • h3
Step 3: 3.1 h2 multiplied by h3 = h(2 + 3) = h5
Final answer: (3•22g4h5)
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