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liraira [26]
2 years ago
5

Line a is purpendicular to line b. if the slope of line a is 7 than what is the slope of line b

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
8 0

The slope of the perpendicular line b is -1/7 if the slope of the perpendicular line a is 7.

According to the question,

Line 'a' is perpendicular to the line 'b'. If the slope of the line 'a' is 7.

The condition of slopes if two lines are perpendicular m₁ m₂ = -1

(7)(m₂) = -1

   m₂ = -1/7

Hence, the slope of the perpendicular line b is -1/7 if the slope of the perpendicular line a is 7.  

Learn more about perpendicular lines here

brainly.com/question/2505127

#SPJ4

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What is 103% of 127 tons???
Pie
%/100=is/off
so you plug in the numbers and cross-multiply.
103times127 equal 13081.
than divide it by 100 the answer is 130.81
8 0
3 years ago
Find the distance between the points (3, -5) and (-6, -5).
Sophie [7]

ANSWER

9

EXPLANATION

We want to find the distance between the points (3, -5) and (-6, -5).

The given points have the same y-coordinates .

This means it is a horizontal line.

We use the absolute value method to find the distance between the two points.

We find the absolute value of the distance between the x-values.

The distance between the two points is

|3--6|=|3+6|=|9|=9

8 0
3 years ago
^!!Howdy howdy!!^
serious [3.7K]

Answer:

1. >; 2. >  

Step-by-step explanation:

1.

     ⅜ (?) 0.295    Convert ⅜ to a decimal fraction

0.375 (?) 0.295

We can use a <em>number line</em> to decide which number is greater.

In Fig. 1 below, when we go from 0.295 to 0.375, we are moving to the <em>RIGHT</em>,  so 0.375 is greater than 0.295.

0.375 >  0.295

2.

-0.770 (?) -4/5    Convert ⅘ to a decimal fraction

-0.770 (?) -0.800

In Fig. 2 below, when we go from -0.80 to -0.77, we are moving to the <em>RIGHT</em>,  so -0.770 is greater than -0.800.

-0.770 > -0.800


3 0
3 years ago
Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have
boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0
3 years ago
A point is represented by a single dot and
evablogger [386]
A letter, which is how you name it. If that is what your asking, of course.
5 0
3 years ago
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