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Vikki [24]
3 years ago
9

Cassie buys a soccer ball that cost 3249 she gives the store clerk $40 how much change should she get back

Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

$7.51

Step-by-step explanation:

I think you meant $32.49*

$40.00

- $ 32.49

-----------------

$ 7.51

Since she's giving the clerk $40.00 for an item that only costs $32.49, you subtract $32.49 from $40.00 to get the amount of change she would get back.

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$925 at 2% interest for 2.4 years. Find the simple interest earned.
mixer [17]

Answer:

£43

Step-by-step explanation:

925×2/100

=£ 18.5

2.4 years =18.5×2.4

=£43

5 0
3 years ago
How many 1/10's are in 2/5?
goblinko [34]
There is 4 1/10's in 2/5.

You do this by turning 2/5 into a fraction with a denominator of 10, so it will be 4/10. 1/10 + 1/10 + 1/10 + 1/10 = 4/10
3 0
4 years ago
Rebecca is making bracelets to sell at a charity event. Each bracelet takes 1 1/4 of a foot of embroidery floss to make.If Rebec
Ivan

Answer:

12

Step-by-step explanation:

She has 15 feet of floss. 15/1.25 is 12.

Hope this helps!!

4 0
3 years ago
Read 2 more answers
Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s
stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.  

Then we have n_{1} = 25, \bar{x}_{1} = 2.04, \sigma_{1} = 0.010 and n_{2} = 20, \bar{x}_{2} = 2.07, \sigma_{2} = 0.015. The pooled estimate is given by  

\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative).  

The test statistic is T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}} and the observed value is t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257. T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value t_{0} falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by 2P(T0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}, i.e.,

-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}

where t_{0.025} is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

-0.03\pm(2.0167)(0.012459)(0.3), i.e.,

(-0.0225, -0.0375)

8 0
3 years ago
Simplify fraction 4/28 and 24/80
Degger [83]

Answer:

1. 1/7

2. 3/10

Step-by-step explanation:

4/28 can be divided by 4

24/80 can be divided by 8

7 0
3 years ago
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