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Setler [38]
2 years ago
11

REALLY HARD QUESTION HELPPPP

Mathematics
1 answer:
svet-max [94.6K]2 years ago
4 0

Answer:

Step-by-step explanation: I did the test and the answer should be A

hope this helps :)

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NEED HELP PLEASE I NEED THE ANSWER
jarptica [38.1K]

Answer:

Step-by-step explanation:

The 2 lines are y=2x+12 (slope of 2 y-intercept at 12) and y=26 (line at y=26).

intersection= (7,26)

7 0
3 years ago
HELPPP MEEEE PLSSSS I WILL GIVE CROWN
emmasim [6.3K]

Answer:

6

Step-by-step explanation:

if you notice here Josiah starts with 250 and Katie starts with 215, and in Josiah's equation he saves 25$ each month while Katie save 45$ each month, in order to find our answer we must multiply there starting amount by how many months.

A: 4 months is <em>incorrect</em> because Katie has 45x4+215 is 335, and Josiah has 25x4+250 is 350, so Katie is still behind

B: 5 months is <em>incorrect </em> because Katie has 45x5+215 is 375, and Josiah has, 25x5+250 which is 375, so they have the same amount of savings

C: 6 months is <em>correct</em>  because Katie has 45x6+215 is 420, and Josiah has, 25x5+250 which is 400 , so Katie has more savings, Thus C is correct

Sorry for the Wait, Your Welcome, And Have An Amazing Day

3 0
3 years ago
Use the limit theorem and the properties of limits to find the horizontal asymptotes of the graph of the function g(x) = x2/x2-2
ElenaW [278]

Answer:

Option b is right.

Step-by-step explanation:

A function is given as

g(x) = \frac{x^2}{x^2-2x-1}

Limit is to be found out for x tends to infinity.

We find that numerator and denominator has the same degree.

HEnce a horizontal asymptote exists

COefficients of leading terms are 1 and 1 respectively

Asymtote would be y =1/11 = 1

Alternate method:

When x tends to infinity, 1/x tends to 0

g(x) =\frac{\frac{1}{x^2} }{1-\frac{2}{x} -\frac{1}{x^2} }

by dividing both numerator and denominator by square of x.

Now take limit as 1/x tends to 0

we get

limit is y tends to 1/1 =1

Hence horizontal asymptote is y =1

8 0
4 years ago
of joseph's vacation pictures, 4/9 were of his family. The remailing photos were of famous landmarks. If 45 photos were of landm
Mila [183]
4/9+5/9= all the pics

45 divided by 9 = to 5
(5/9)

so...

4*9=36

i m almost positive
6 0
3 years ago
Quadrilateral $ABCD$ has right angles at $B$ and $D$, and $AC=3$. If $ABCD$ has two sides with distinct integer lengths, then wh
Jet001 [13]

Answer:

34 is the answer

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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