Answer:
A is 1.
B is 2.
C is 3.
PEMDAS
1 +2(3) = 1 + 6 = 7
to the person who said I made a mistake, I didn't lol
heres the indepth part since you need it:
1 + 1 + 1 = 3
2 + 2 + 1 = 5
3 + 3 + 2 = 8
if you made the error of thinking it was (1+2), then you misunderstood the problem. it would then be 3x3 which is 9.
Hey, Jaya21!
Great question:)
16*53=848
Remainder:5
I hope this helps=)
Although the points do not sit exactly on integer coordinates, we can round their coordinates and say that
![A \approx (10,5),\ B\approx (17,13),\ C \approx (20,5),\ D \approx (37,7),\ E \approx (55,23)](https://tex.z-dn.net/?f=%20A%20%5Capprox%20%2810%2C5%29%2C%5C%20B%5Capprox%20%2817%2C13%29%2C%5C%20C%20%5Capprox%20%2820%2C5%29%2C%5C%20D%20%5Capprox%20%2837%2C7%29%2C%5C%20E%20%5Capprox%20%2855%2C23%29%20)
Now, remember that the first coordinate represents the number of events, and the second coordinate represents the number of stamps. So, if we want the number of events to be four times the number of stamps, we need a point whose first coordinate is four times the second.
This is the case for point C, because its first coordinate is about 20, and its second coordinate is about 5, and 20 is four times 5.
Unless Tonya purchase a insurance warranty on rental car.