24/42*14/42*18/42=? -As a fraction in simplest form?
1 answer:
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Answer:
b11 = -14
b12 = 9
b13 = 8
Step-by-step explanation:
* Lets revise some notes to solve the problem
- Any matrix has a dimension m × n, where m is the number of rows
and n the number of columns
- We can add matrices with same dimensions
* Now lets solve the problem
∵
- Let
∴
- Lets add and find the missing
* Lets start with the first rows
∵ b11 + 15 = 1 ⇒ subtract 15 from both sides
∴ b11 = -14
∵ b12 + -7 = 2 ⇒ add 7 to both sides
∴ b12 = 9
∵ b13 + 4 = 12 ⇒ subtract 4 from both sides
∴ b13 = 8
* Now lets start with the second rows
∵ b21 + 0 = 4
∴ b21 = 4 ⇒ given
∵ b22 + 1 = 0 ⇒ subtract 1 from both sides
∴ b22 = -1 ⇒ given
∵ b23 + 2 = 2 ⇒ subtract 2 from both sides
∴ b23 = 0 ⇒ given
The numbers are 1 and 18
<em><u>Solution:</u></em>
Let the smaller number be "x"
Let the larger number be "y"
Given that smaller of two numbers is five less than the larger number
smaller number = one - third of larger number - 5
3x = y - 15
y = 3x + 15 ------- eqn 1
Half the larger added to the smaller is 10
y + 2x = 20 ------- eqn 2
Let us solve eqn 1 and eqn 2
Substitute eqn 1 in eqn 2
3x + 15 + 2x = 20
5x = 20 - 15
5x = 5
<h3>x = 1</h3>From eqn 1,
y = 3(1) + 15 = 18
<h3>y = 18</h3>Thus the numbers are 1 and 18