Question

Y is inversely proportional to the square of x. If Y = 2 when x = 8, then Y = , when x is_______.

Answer 1

The value of x when y =2 is 8

How to solve for x?

The inverse proportion to the square of x represented as:

k = yx^2

Where

k represents the constant of proportion

When y = 2, x = 8.

So, we have:

k =2 * 8^2

k =128

Substitute k = 128 in k = yx^2

So, we have:

yx^2 = 128

When y = 2, we have:

2x^2 = 128

Divide by 2

x^2 = 64

Take the square roots

x = 8

Hence, the value of x when y =2 is 8

Read more about variation at:

brainly.com/question/14254277

#SPJ1