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lina2011 [118]
2 years ago
7

Please help me! Giving brainliest!

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
5 0

Using it's formula, the surface area of the figure is:

A. S=2332 m²

<h3>What is the surface area of a rectangular prism?</h3>

The surface area of a rectangular prism of dimensions l, w and h is given by:

S = 2(lw + lh + wh)

In this problem, the dimensions are:

35m, 9m, 16m

Hence the surface area of the rectangular prism is:

S = 2(35 x 9 + 35 x 16 + 16 x 9) = 2038 m².

<h3>What is the surface area of a cube?</h3>

The surface area of a cube of side length l is given by:

S = 6l².

In this problem, we have that l = 7 m, hence the surface area is:

S = 6 x 7² = 294 m².

<h3>What is the total surface area?</h3>


The total surface area is the sum of the surface areas, hence:

T = 2038 m² + 294 m² = 2332 m².

Which means that option A is correct.

More can be learned about surface area at brainly.com/question/13030328

#SPJ1

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Standard deviation measures Total risk while beta measures Systematic risk.

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Analyze the diagram below and complete the instructions that follow.
lora16 [44]

Answer:

\displaystyle y=2\sqrt{6}

\displaystyle x=2\sqrt{2}

Step-by-step explanation:

<u>Trigonometric Ratios </u>

The ratios of the sides of a right triangle are called trigonometric ratios.

The longest side of the right triangle is called the hypotenuse and the other two sides are the legs.

Selecting any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.

The image provided shows a right triangle whose hypotenuse is given. We are required to find the value of both legs.

Let's pick the angle of 30°. Its adjacent side is y. We can use the cosine ration, which is defined as follows:

\displaystyle \cos 30^\circ=\frac{\text{adjacent leg}}{\text{hypotenuse}}

\displaystyle \cos 30^\circ=\frac{y}{4\sqrt{2}}

Solving for y:

y=4\sqrt{2}\cos 30^\circ

Since:

\cos 30^\circ=\frac{\sqrt{3}}{2}

\displaystyle y=4\sqrt{2}\frac{\sqrt{3}}{2}

Simplifying:

\displaystyle y=2\sqrt{6}

Now we use the sine ratio:

\displaystyle \sin 30^\circ=\frac{\text{opposite leg}}{\text{hypotenuse}}

\displaystyle \sin 30^\circ=\frac{x}{4\sqrt{2}}

Solving for x:

x=4\sqrt{2}\sin 30^\circ

Since:

\sin 30^\circ=\frac{1}{2}:

\displaystyle x=4\sqrt{2}\frac{1}{2}

Simplifying:

\displaystyle x=2\sqrt{2}

The choices are not clear, but it seems like the correct answer is C.

\boxed{\displaystyle y=2\sqrt{6}}

\boxed{\displaystyle x=2\sqrt{2}}

6 0
3 years ago
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