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maria [59]
3 years ago
11

The sum of three numbers is 99. The third number is 3 times the first . The second number is 9 more than the first. What are the

numbers?
Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer: This can be written as x + (x-9) + 3(x-9) = 99

5x - 36 = 99

5x = 135

x = 135/5 = 27

You can now just plug in the value of x for each of the initial terms to get:

n1 = 27

n2 = 18

n3 = 54

Step-by-step explanation:

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115 minutes

Step-by-step explanation:

Range = highest observation - smallest observation

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Therefore range = 130 - 15

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3 years ago
For any nonempty set $T$ whose elements are positive integers, define $f(T)$ to be the square of the product of the elements of
guapka [62]

Answer:

We get

$225+324+441+576+784+1125+2304+3136+4900+11025=24840$

Step-by-step explanation:

$(1\cdot 3\cdot 5)^2 = 15^2 = 225$

$(1\cdot 3\cdot 6)^2 = 18^2 = 324$

$(1\cdot 3\cdot 7)^2 = 21^2 = 441$

$(1\cdot 4\cdot 6)^2 = 24^2 = 576$

$(1\cdot 4\cdot 7)^2 = 28^2 = 784$

$(1\cdot 5\cdot 7)^2 = 35^2 = 1125$

$(2\cdot 4\cdot 6)^2 = 48^2 = 2304$

$(2\cdot 7\cdot 7)^2 = 56^2 = 3136$

$(2\cdot 5\cdot 7)^2 = 70^2 = 4900$

$(3\cdot 5\cdot 7)^2 = 105^2 = 11025$

We get

$225+324+441+576+784+1125+2304+3136+4900+11025=24840$

4 0
3 years ago
Please help math
Naddika [18.5K]
   
\displaystyle\\
15(2a - 2) = 5(a^2 -1) \\  \\ 
30a - 30 = 5a^2-5\\\\
-5a^2 + 30a -30 + 5 =0\\\\
-5a^2 + 30a -25 =0 ~~~~~\Big| \times (-1) \\\\
5a^2 - 30a +25 = 0~~~~~\Big| : 5 \\\\
a^2 - 6a +5 = 0 \\  \\ 
a_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}= \frac{6\pm \sqrt{36-20}}{2}= \frac{6\pm \sqrt{16}}{2}=\frac{6\pm 4}{2}= \boxed{3\pm 2} \\  \\ 
a_1 = 3+ 2 = \boxed{5}\\\\
a_2 = 3-2 = \boxed{1}



8 0
3 years ago
Read 2 more answers
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