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lisabon 2012 [21]
4 years ago
8

An empty bucket is placed under a faucet dripping at a constant rate of 4 milliliters per minute. With the given information, wh

ich of these statements is a reasonable conclusion? There will be 24 milliliters of water in the bucket after 16 hour. There will be 60 milliliters of water in the bucket after 14 hour. There will be 160 milliliters of water in the bucket after 20 minutes. There will be 100 milliliters of water in the bucket after 40 minutes.
Mathematics
2 answers:
GarryVolchara [31]4 years ago
8 0

the answer is true i think

aleksandr82 [10.1K]4 years ago
6 0

Answer:

it is true

Step-by-step explanation:

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Find the zeros and verify x^2 +2x-180
Arada [10]

Answer:

Rounded to the nearest tenth they are -14.5 and 12.5

Step-by-step explanation:

The zeros of a function are the x-intercepts or roots where the function crosses the x-axis. To find them, graph the function x^2 +2x-180 and zoom in on the x-axis.

See attached picture.

6 0
3 years ago
Is the value of 8 in 345,802 ten times greater or smaller than the value of 8 in 758,910
german

Answer:

Yes

Step-by-step explanation:

One is in the hundreds and one is in the thousands. 100x10=1000

7 0
3 years ago
Help please it’s due soon <br><br> ( DISTANCE IS A MISTAKE )
katrin [286]

Answer:

speed

time

faster

greater

You can fill in these words in the blanks.

4 0
3 years ago
3/9+2/9=?/9<br> Help a brother out
Ahat [919]

Answer:

5/9

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
4 years ago
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