Match each equation to its factorized version and solution. 24x – 6x2 = 0 2x(x 3) = 0 solution: x = 0, x = -3 14x – 7x2 = 0 6x(4

Question

2 years ago

6

– x) = 0 solution: x = 0, x = 4 2x2 6x = 0 x(4 – x) = 0 solution: x = 0, x = 4 4x – x2 = 0 7x(2 – x) = 0 solution: x = 0, x = 2

1 answer:

Archy [21] · Answer 1 · 2023-08-31T09:18:10+03:00

So, The correct match of these quadratic equations are
Equation A has a solution x = 3 and x = 0.

Equation B has a solution x = 2 and x = 4.

Equation C has a solution x = -3 and x = 0.

Equation D has a solution x = 4 and x = 0.

According to the equation

we have given that the some equation with there values of the x and we have to find and match the correct statement with the given values of x.

So, For this purpose, we know that the

The given quadratic equations are:

A. 24x – 6x^2 = 0 and 2x(3x) = 0 with solution x = 0, x = -3

B. 14x – 7x^2 = 0 and 6x(4 – x) = 0 with solution x = 0, x = 4

C. 2x^2+ 6x = 0 and x(4 – x) = 0 with solution x = 0, x = 4

D. 4x – x^2 = 0 and 7x(2 – x) = 0 with solution x = 0, x = 2

And now we solve it

So,

Take A.

24x – 6x^2 = 0 and 2x(3x) = 0

6x(3 -x) = 0 And 6x^2 = 0

here x = 3 and x = 0.

And

Take B.

14x – 7x^2 = 0 and 6x(4 – x) = 0

7x(2 -x) = 0 And 6x(4 – x)= 0

here x = 2 and x = 4.

And

Take C.

2x^2+ 6x = 0 and x(4 – x) = 0

2x(x +3) = 0 And x(4 – x)= 0

here x = -3 and x = 0.

And

Take D.

4x – x^2 = 0 and 7x(2 – x) = 0

x(4 -x) = 0 And 7x(2 – x)= 0

here x = 4 and x = 0.

So, The correct match of these quadratic equations are
Equation A has a solution x = 3 and x = 0.

Equation B has a solution x = 2 and x = 4.

Equation C has a solution x = -3 and x = 0.

Equation D has a solution x = 4 and x = 0.

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