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andreev551 [17]
3 years ago
9

What is the value of x?

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0

Answer:

X = 5°

Step-by-step explanation:

180° on a straight line.

180 - 100 = 80 angle ABC = 80°

angle ACB is vertically opposite to the 60° given

ACB = 60°

180 - 80 - 60 = 7x+5

40 = 7x + 5

7x = 35

X = 5

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jolli1 [7]
Y=1/2x+4
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7 0
3 years ago
Read 2 more answers
The slope of the line graphed
katrin2010 [14]

 

\displaystyle\bf\\ \text{\bf The slope = }~~\frac{y_2-y_1}{x_2-x_1}=\frac{4-(-4)}{4-(-1)}=\frac{4+4}{4+1}=\boxed{\bf\frac{8}{5}}




5 0
3 years ago
In order for a relation to be a function, there cannot be duplicate domain values that have different range values. for example,
mylen [45]
True, because it makes the function fail the vertical line test
8 0
3 years ago
19. The cost function of a product is C(Q) = 3Q² +8 and the demand function of the same product is P =1/3 Q² — 10Q + 105, where
Kamila [148]

The marginal revenue at the output level 4 is 24, marginal revenue at the output level 4 is 41, and marginal profit at the output level 4 is 17.

<h3>What is a marginal cost?</h3>

It is defined as the cost showing an increase in the cost when the number of units produced increases, In simple words it is the ratio of the cost to quantity.

We have a cost function of a product:

C(Q) = 3Q² +8

a) To find the marginal cost to differentiate it with respect to Q and plug

Q = 4:

C'(Q) = 6Q

C'(4) = 6(4) = 24

b) R(Q) = P×Q

\rm R(Q) = (\dfrac{1}{3} Q^2 - 10Q + 105)Q

\rm R(Q) = \dfrac{1}{3} Q^3 - 10Q^2 + 105Q

R'(Q) = Q² - 20Q + 105

Plug Q = 4

R'(Q) = (4)² - 20(4) + 105

R'(Q) = 41

c) Marginal profit:

MP(Q)  = R(Q) - C(Q)

After calculating:

\rm MP(Q)  = \dfrac{1}{3}Q^3-13Q^2+105Q-8

MP'(Q) = Q² - 26Q + 105

Plug Q = 4

MP'(Q) = 16 - 104 + 105 = 17

Similar, we can find the maximum profit.

Thus, the marginal revenue at the output level 4 is 24, marginal revenue at the output level 4 is 41, and marginal profit at the output level 4 is 17.

Learn more about the marginal cost here:

brainly.com/question/7781429

#SPJ1

3 0
2 years ago
What is the length of the focal width x=-1/8y^2
Levart [38]
The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.

<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2

p = -2, h=0, k=0</span><span>

focal width = |4*(-2)| = 8

The answer to your question is that the length of the focal width is equal to 8.</span>
3 0
3 years ago
Read 2 more answers
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