<h2>9.</h2><h3>Given</h3>
<h3>Find</h3>
- linear approximation to the volume when the radius increases 0.4 cm
<h3>Solution</h3>
The equation for volume of a sphere is
... V = (4/3)π·r³
Differentiating gives
... dV = 4π·r²·dr
Filling in the given numbers gives
... change in volume ≈ 4π·(15 cm)²·(0.4 cm)
... = 360π cm³ ≈ 1130.97 cm³ . . . . . . volume of layer 4mm thick
<h2>11.</h2><h3>Given</h3>
- an x by x by 2x cuboid with surface area 129.6 cm²
- rate of change of x is 0.01 cm/s
<h3>Find</h3>
<h3>Solution</h3>
The area is that of two cubes of dimension x joined together. The area of each such cube is 6x², but the two joined faces don't count in the external surface area. Thus the area of the cuboid is 10x².
The volume of the cuboid is that of two cubes joined, so is 2x³. Then the rate of change of volume is
... dV/dt = (d/dt)(2x³) = 6x²·dx/dt
We know x² = A/10, where A is the area of the cuboid, so the rate of change of volume is ...
... dV/dt = (6/10)A·dx/dt = 0.6·(129.6 cm²)(0.01 cm/s)
... dV/dt = 0.7776 cm³/s
Answer:
?
Step-by-step explanation:
X-2y = 3
-2y=3-x move the x over to the other side
-y=3/2 -1/2x divide both sides by 2
y=1/2x - 3/2 divide both sides by -1
Answer:
4 1/6 inches
Step-by-step explanation:
A triangle has sides of LaTeX: 1\frac{1}{6}1 1 6 inches, LaTeX: 1\frac{1}{3}1 1 3 inches, and LaTeX: 1\frac{2}{3}1 2 3 inches. What is the perimeter of the triangle? Make sure your answer is in simplest form.
Perimeter of Triangle = Side a + Side b + Side c
Perimeter of the Triangle =
( 1 1/6 + 1 1/3 + 1 2/3) inches
Lowest common denominator = 6
= 1 + 1 + 1 +(1/6 + 1/3 + 2/3)
= 3 + (1 + 2 + 4/6)
= 3 + 7/6
= 3 + 1 1/6
= 4 1/6 inches
There's no such concept as "close" in mathematics. Or at least, you have to specify when you consider two numbers to be "close".
All we can say is that, since 3/4=0.75, the two numbers are
units apart. Is this small enough to consider them as "close"? Is this big enough to consider them not to be "close"?
You should clarify more what you mean so that a definitive answer can be given.
