Answer:
E) is correct, 2/3
Step-by-step explanation:
The points that are 20 inches apart from P form a circle that contains Q. We can suppose that P is in the position (0,0) and Q in the position (20,0) (we can rotate and move the circle without making any effect on the probability).
A point in the circle at distance 20 of Q has the form (20 cos(Ф), 20 sen(Ф) ) for certain angle Ф between 0 and 2π. Since it is at distance 20 of Q, we have that (20-20cos(Φ))² + (0-20sen(Φ))² = 20²=400, thus
400 - 800 cos(Φ) + 400cos²(Φ) + 400sen²(Φ) = 800-800cos(Φ) = 400, so
400 = 800cos(Φ)
cos(Φ) = 1/2
By looking at a trigonimetric table, you can find that Φ is either π/3 or 2π-π/3 = 5π/3.
As a result, the angles that will give you a point R at distance from Q greater than 20 are between π/3 and 5π/3, hence , the points that are a distance greater than 20 form a chord of length 20*(5π/3-π/3) = 80π/3. Comparing this with the perimeter of the circle (20*2π = 40π), this gives us a probability of 80π/3 / 40π = 2/3 that the point R is closer to P than it is to Q.
Answer:
-30/49
Step-by-step explanation:
You multiply the numbers, then add the negative symbol, when you multiply the numbers, you get:
10/7*3/7 which equals 30/49, which means the answer is -30/49
Answer:
10/37
Step-by-step explanation:
Total = 10 + 6 + 5 + 8 + 4 + 4
= 37
P(boy from Marigold) = 10/37
Answer:
309in²
Step-by-step explanation:
Area of an octagon is expressed as;
A=2(1+√2)a²
a is the side length of the octagon
Given
a = 8
Substitute into the formula
A = 2(1+√2)(8)²
A = 2(1+√2)(64)
Expand
A = 2(64+64√2)
A = 128+128√2
A = 128+128(1.414)
A = 128+181.01
A = 309in²
Hence the area of the octagon is 309in²