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irina [24]
3 years ago
7

At a swim meet 20 medals were a warded. Four were gold metals 45% of the metals were silver the rest were bronze. What percent o

f the medals awarded were bronze
Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

Answer:

35%

Step-by-step explanation:

To figure out the percentage of bronze medals, we must figure out the percentages of the gold and silver medals first.

We already know that 45% of the medals were silver.

We know that 4 of the 20 medals were gold.

4/20 as a percentage would be 20/100, or 20%.

So, 20% of the medals were gold, and 45% of them were silver.

45% + 20% = 65%

100% - 65% = 35%

So, 35% of the medals awarded were bronze.

<em>I would appreciate brainliest, if not that's ok!</em>

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Answer:

It is 7 2/11 is less then 7 4/10

Step-by-step explanation:

You do not have to worry about the whole number because they are the same. You have to compare the fractions, so if comparing fractions 10 is less then 11 so 1/10 has a larger space then 1/11. That is how i got the answer. Hope this helps. Am I right?

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2 years ago
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Subtract 30 from both sides

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Studentka2010 [4]

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What is this problem simplified
Svetlanka [38]
\frac{x^2 - 5x-6}{x^2 - 36}

You can begin to simplify this by factoring both the numerator and denominator:

\frac{x^2 - 5x-6}{x^2 - 36} = \frac{(x-6)(x+1)}{(x-6)(x+6)}

Next, cancel out any common factors in both the numerator and denominator:

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3 years ago
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goblinko [34]

Answer:

The answer to your question is:

a)   f(a) -2 = a² - 3

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Step-by-step explanation:

a. f(a) - 2 = (a)² - 1 - 2

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b. f(a - 2) = (a - 2)² - 1

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c. f(b + d) = (b + d)² - 1

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3 years ago
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