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Sati [7]
2 years ago
10

(50 POINTS!!!) find the total surface area and volume, then multiply by $0.004. please show your work!!

Mathematics
1 answer:
mrs_skeptik [129]2 years ago
6 0

The Total surface area of the square pyramid = 115.2 in.²

The Volume of the square pyramid = 1,024 in.³.

<h3>What is the Total Surface Area of a Square Pyramid?</h3>

The total surface are of a square pyramid is given as: TSA = SA = 1/2(P × l), where:

P = perimeter of the square base

l = slant height of the pyramid

<h3>What is the Volume of a Square Pyramid?</h3>

The volume of a square pyramid = 1/3(a³ × h), where:

a = edge of the square base

h = height of the pyramid

Find the Total surface area of the Pyramid:

P = 4(a) = 4(8) = 32 in.

l = 7.2 in.

Total surface area of the square pyramid = 1/2(32 × 7.2)

Total surface area of the square pyramid = 115.2 in.²

Volume of the square pyramid:

a = 8 in.

h = 6 in.

Volume of the square pyramid = 1/3(8³ × 6)

Volume of the square pyramid = 1,024 in.³

Learn more about the square pyramid on:

brainly.com/question/3688277

#SPJ1

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3 years ago
Read 2 more answers
Convert from rectangular to polar coordinates: note: choose rr and θθ such that rr is nonnegative and 0≤θ&lt;2π0≤θ&lt;2π (a)(9,0
DochEvi [55]

Answer:

Step-by-step explanation:

Convert rectangle (x , y) to polar coordinates ( r , θ)

x=r  \cos \theta, y= r \sin \theta

r=\sqrt{x^2+y^2} , \theta =tan^-^1 (\frac{y}{x} )

a) converts (9, 0) to polar coordinates  ( r , θ)

r=\sqrt{x^2+y^2} \\\\=\sqrt{9^2+0} \\\\=9

\theta= \tan^-^1 (\frac{0}{9} )\\\\=0

b) Convert (18,\frac{18}{\sqrt{3} } ) to polar coordinates ( r, θ)

r = \sqrt{18^2+(\frac{18}{\sqrt{3} })^2 } \\\\=\sqrt{324+108} \\\\=\sqrt{432}

\frac{x}{y} \theta = \tan^-^1(\frac{\frac{18}{\sqrt{3} } }{18} )\\\\= \tan ^-^1(\frac{1}{\sqrt{3} } )\\\\= \frac{\pi}{6}

c)  converts (-5, 5) to polar coordinates  ( r , θ)

r =\sqrt{(-5)^2+(5)^2} \\\\=\sqrt{50} \\\\=5\sqrt{2}

\theta=\tan^-^1(\frac{5}{-5} )\\\\= \tan^-^1(-1)\\\\=\frac{3\pi}{4}

d)  converts (-1, √3) to polar coordinates  ( r , θ)

r=\sqrt{(-1)^2+(\sqrt{3})^2 } \\\\= \sqrt{4} \\\\=2

\theta=\tan^-^1(\frac{\sqrt{3} }{-1} )\\\=\tan^-^1(-\sqrt{3} )\\\\=\frac{2\pi}{3}

= \frac{2\pi}{\sqrt{3} }

6 0
3 years ago
What estimate can you make for 1/2 and 4/6?
densk [106]
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3 years ago
 Solve the system of inequalities and indicate all the integers which are in the solution set:
elena-s [515]
1.) a>10
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How I got it: 1.) Subtract 3 from both sides, leaving -2a<10.
2.) Divide by -2 from both sides, remember to flip the inequality sign when dealing with negatives. This leaves you with a>10.
For number 2.) I divided both sides by 5, leaving a<3.5, though this answer may be wrong.
8 0
3 years ago
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