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Sati [7]
2 years ago
10

(50 POINTS!!!) find the total surface area and volume, then multiply by $0.004. please show your work!!

Mathematics
1 answer:
mrs_skeptik [129]2 years ago
6 0

The Total surface area of the square pyramid = 115.2 in.²

The Volume of the square pyramid = 1,024 in.³.

<h3>What is the Total Surface Area of a Square Pyramid?</h3>

The total surface are of a square pyramid is given as: TSA = SA = 1/2(P × l), where:

P = perimeter of the square base

l = slant height of the pyramid

<h3>What is the Volume of a Square Pyramid?</h3>

The volume of a square pyramid = 1/3(a³ × h), where:

a = edge of the square base

h = height of the pyramid

Find the Total surface area of the Pyramid:

P = 4(a) = 4(8) = 32 in.

l = 7.2 in.

Total surface area of the square pyramid = 1/2(32 × 7.2)

Total surface area of the square pyramid = 115.2 in.²

Volume of the square pyramid:

a = 8 in.

h = 6 in.

Volume of the square pyramid = 1/3(8³ × 6)

Volume of the square pyramid = 1,024 in.³

Learn more about the square pyramid on:

brainly.com/question/3688277

#SPJ1

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Please give me the answer please
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If there are 4 trucks then the first truck weighs x
then x+2tons
then x+4tons
then x+6tons = 32tons
so 4x+12=32
         -12   -12
     /4         /4
x=5 
so plug it back in 
truck 1= 5tons or 10,000lbs
truck 2= 7tons or 14,000lbs
truck 3= 9tons or 18,000lbs
truck 4= 11tons or 22,000lbs

5 0
3 years ago
What is the equation?
Illusion [34]

Answer:

y=22x

Step-by-step explanation:

If x=1 and y=22 then y=22x

4 0
3 years ago
What is the 4(4x)+(x) equal!?
e-lub [12.9K]

4(4x)+(x)

= 16x+x

Combine like terms

16x+x

(16x+x)

= 17x

x=17


I hope that's help ! Good night .

5 0
3 years ago
In parallelogram QRST QS RT Is QRST a rectangle ?
fomenos

Answer:

The correct option is A.

Step-by-step explanation:

It is given that the QRST is a parallelogram and the diagonals QS and RT are congruent.

According to the property of parallelogram if the length of diagonals are same, then the parallelogram is rectangle. We can also prove it.

Let QRST be an parallelogram and QS=RT.

In triangles QRT and RQS.

RT=QS         (Diagonals)

QR=QR         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QRT and triangle RQS are congruent.

By CPCT,

\angle R=\angle Q

Since the sum of two consecutive angles of a parallelogram is 180 degree.

\angle R+\angle Q=180

2\angle R=180

\angle R=90

Therefore the measure of angle R and angle Q are 90 degree.

Similarly in triangle QST and RTS,

RT=QS         (Diagonals)

ST=ST         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QST and RTS are congruent.

By CPCT,

\angle S=\angle T

Since the sum of two consecutive angles of a parallelogram is 180 degree.

Therefore the measure of angle S and angle T are 90 degree.

Since the measure of all interior angles of QRST are 90 degree, therefore the parallelogram QRST  is a rectangle.

6 0
4 years ago
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What is the value of logo<br> 36?
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If you mean log, then 1.556303

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