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o-na [289]
4 years ago
5

How many grams of ethanol, ch3ch2oh, should you dissolve in water to make 1.20 l of vodka (which is an aqueous solution that is

6.86 m ethanol)?
Chemistry
1 answer:
maria [59]4 years ago
8 0
The concentration is expressed in molarity or moles solute per liters solution. The molar mass of ethanol is 46 g/mol. To obtain a 1.2 L of vodka, the following stoichiometric calculation is done:

6.86 mol/L * 1.2 L * (46g/mol) = 378.672 g of ethanol is needed
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Answer:

Option A. 6.75 (6.20/85.6)

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 6.2cm³

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The final concentration can be obtained by using the dilution formula as show below:

C1V1 = C2V2

6.75 x 6.2 = C2 x 85.6

Divide both side by 85.6

C2 = (6.75 x 6.2) /85.6

C2 = 6.75 (6.2 / 85.6).

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