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Sindrei [870]
3 years ago
10

20+ points

Chemistry
1 answer:
bixtya [17]3 years ago
6 0
1. 4Fe + 3O2 yields 2Fe2O3 (some of the numbers are subscripts, just to let you know)

2. Its a combination reaction
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A train in Japan can travel 813.5 miles in 5 hours
Anastaziya [24]

Answer:

162.7miles/hr

Explanation:

Given parameters:

Distance covered by the train  = 813.5miles

Time taken  = 5hours

Unknown:

Speed of the train  = ?

Solution:

Speed is a physical quantity.

It is mathematically expressed as;

      Speed  = \frac{distance}{time}

So, input parameters and solve;

   Speed  = \frac{813.5}{5}  = 162.7miles/hr

8 0
3 years ago
KBr + AgNO3 → AgBr + KNO3<br><br><br> Which two chemicals are products in the chemical reaction?
iragen [17]

Answer:

Products are AgBr and KNO3

4 0
3 years ago
What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M
Fed [463]

<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>

What is benzoic acid found in?

  • Some natural sources of benzoic acid include: ​Fruits:​ Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
  • ​Spices:​ Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 =  0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

pH = pKa + log\frac{base}{acid}

4.2 + log\frac{0.05}{0.045} = 4.245

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

pH = pKa + log\frac{base}{acid}

4.245 = 3.75 + log\frac{base}{acid}

log\frac{base}{acid} = 0.5

\frac{base}{acid} = 3.162

Now we must solve the equation above. This will be done using the following values

\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

brainly.com/question/24052816

#SPJ4

3 0
2 years ago
How did he know that the nucleus was positively charged?
Harman [31]
'cause alphe-particle which was +ve charge, get repulsion from the atom, so he deducted that.......
8 0
3 years ago
HELP PLS- One student made the incomplete diagram shown below to represent the relationship between magma, igneous rocks, and me
Naya [18.7K]

Answer:

ignious b

Explanation:

burns on lava rock

5 0
3 years ago
Read 2 more answers
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