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Ratling [72]
2 years ago
6

One night Ricky and her brother Micky decide to have some fun at their father's sweet shop. In the

Mathematics
1 answer:
vova2212 [387]2 years ago
8 0

Answer:

a) 3034

b)249

Step-by-step explanation:

jellyb beans: 7*135= 945

choc buds: 9*121=1089

smarties: 12*70=840

liquorice sticks: 32*5=160

a) the total number of sweets: 945 + 1089 + 840 + 160 = 3034

b) the difference between the number of choc buds and the number of smarties: 1089 - 840 = 249

<em>P.S. Hope it helps. If you have any questions, feel free to ask them in the comment section below. I'll be happy to help. Have a wonderful day!</em>

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Angle 1 and angle 3 are vertically opposite angles. And both angles are congruent with each other.

<h3>What is an angle?</h3>

The angle is the distance between the intersecting lines or surfaces. The angle is also expressed in degrees. The angle is 360 degrees for one complete spin.

Supplementary angle - Two angles are said to be supplementary angles if their sum is 180 degrees.

Line L and line M intersect each other.

Angle 1 and angle 2 are supplementary angles.

∠1 + ∠2 = 180°         ...1

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∠2 + ∠3 = 180°        ...2

From equations 1 and 2, then we have

∠1 + ∠2 = ∠2 + ∠3

∠1 = ∠3

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1 year ago
Find the point-slope equation for the line
rusak2 [61]

Answer:

y-10=5(x-15)

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3 0
3 years ago
Solve for the missing variable.
tigry1 [53]
There wasn't much to go off of but based of the information you've gave me the answer would be 7.68=6.28
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3 years ago
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Express x^2y^2+x^2+y^2+1
Hitman42 [59]

Answer:

( y^2 +1) ( x^2+1)

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3 years ago
9 to the power 3 + 3 to the power 2 + 6 to the power 3 + 15 power 2 equals to how much
Llana [10]
Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!


So-------

9^3=729

3^2=9

6^3=216

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Now that we have that figured out, we can add them together, wish is simple. 729 + 9 + 216 + 225= 1,179.



Therefore, your final answer will be 1,174.




If you have any questions on this, I'm happy to help you. :)




3 0
3 years ago
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