If DH = (4x + 10) in. and HI = (2x − 4) in., then x =_______ , HI =_______ , and ID = _________
1 answer:
You might be interested in
Yay, I like das stuff
I think I learned the washer method
goes like this
ok, so
actuallly, this is easier
y=49-x^2 and
y=0
see when they intersect again
they intersect at -7 and 7
if we do integrate from -7 to 7, then it wil give 0 (because integration is area under the curve), so note that they are same both sides so integrate from 0 to 7 then double the volume to get both sides
so it can't be C or D
It also can'nt be A because it should not be multipied by 4, it should be multipied by 2
basically, we don't need the washer method
remember, area=pir^2
the disk method then
we are summing up all the radii disks and squareing them
but doubleing them so
no idea why we need the inside part to be x(49-x^2), that is intersting
I think I learned the washer method
goes like this
ok, so
actuallly, this is easier
y=49-x^2 and
y=0
see when they intersect again
they intersect at -7 and 7
if we do integrate from -7 to 7, then it wil give 0 (because integration is area under the curve), so note that they are same both sides so integrate from 0 to 7 then double the volume to get both sides
so it can't be C or D
It also can'nt be A because it should not be multipied by 4, it should be multipied by 2
basically, we don't need the washer method
remember, area=pir^2
the disk method then
we are summing up all the radii disks and squareing them
but doubleing them so
no idea why we need the inside part to be x(49-x^2), that is intersting