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2 years ago

Find the midsegment of the triangle which is parallel to CA.

Mathematics

2 answers:

stich3 [128]2 years ago

8 0

Answer:

$\fbox {EG}$

Step-by-step explanation:

Based on the given diagram, we can clearly see the midsegment (lies in the middle of the figure) that is parallel to AC is EG

I hope it helped you solve the problem.

Good luck on your studies!

Nataliya [291]2 years ago

6 0

Answer:

$\pmb{ \pink{QUESTION�}}$

Find the midsegment of the triangle which is parallel to CA.

$\pmb{ \pink{ANSWER:-}}$

Tip

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

$\frak{Explanation:-}$

We have to find the segment which is parallel to CA.

From the given data,

The segment EG is the midsegment of the triangle $\triangle$ ABC.

So we have,

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

$\implies\rm{midsegment \: EG \: parallel \: to \: CA}$

$\frak{RainbowSalt}$ ~

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In 2026 car will have a value of $5,000.

Step-by-step explanation:

We have been given that Jack bought a new car in 2014 for 28,000. If the value of the car decreases by 14% each year.

Since we know that an exponential function is in form: $y=a*b^x$ , where,

a = Initial value,

b = For decay or decrease b is in form (1-r), where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

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Upon substituting a =28,000 and r=0.14 in exponential decay function we will get,

$y=28,000(1-0.14)^x$ , where x represents number of years after 2014.

Therefore, the function $y=28,000(0.86)^x$ represents the value of car x years after 2014.

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$5,000=28,000(0.86)^x$

Let us divide both sides of our equation by 28,000.

$\frac{5,000}{28,000}=\frac{28,000(0.86)^x}{28,000}$

$0.1785714285714286=(0.86)^x$

Let us take natural log of both sides of our equation.

$ln(0.1785714285714286)=ln((0.86)^x)$

Using natural log property $ln(a^b)=b*ln(a)$ we will get,

$ln(0.1785714285714286)=x*ln(0.86)$

$\frac{ln(0.1785714285714286)}{ln(0.86)}=\frac{x*ln(0.86)}{ln(0.86)}$

$\frac{-1.7227665977411033893}{-0.1508228897345836}=x$

$x=11.422447\approx 12$

As in the 12th year after 2014 car will have a value of $5,000, so we will add 12 to 2014 to find the year.

$2014+12=2026$

Therefore, in 2026 car will have a value of $5,000.

6 0

3 years ago

Read 2 more answers

Find the midsegment of the triangle which is parallel to CA.​

Find the midsegment of the triangle which is parallel to CA.