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Nadya [2.5K]
2 years ago
6

when tetanus affects infants,it has been observed that only 10% recovers.in a random sample of5 infants affected by tetanus,what

is the probability that only two will recover
Mathematics
1 answer:
shutvik [7]2 years ago
6 0

In a random sample of 5 infants affected by tetanus, the probability that only two will recover is 7.29%

<h3>How to solve binomial probability?</h3>

The formula for binomial probability is;

P(X = x) = ⁿCₓ * p^(x) * (1 - p)^(n - x)

where;

p is probability of success

q = 1 - p is probability of failure

n is sample size

x is number of successes

We are given;

p = 10% = 0.1

n = 5

x = 2

Thus;

P(X = 2) = ⁵C₂ * 0.1² * (1 - 0.1)⁵ ⁻ ²

P(X = 2) = 0.0729

P(X = 2) = 7.29%

Thus, in a random sample of 5 infants affected by tetanus, the probability that only two will recover is 7.29%

Read more about Binomial Probability at; brainly.com/question/15246027

#SPJ1

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