<u>Given</u>:
If you are dealt 4 cards from a shuffled deck of 52 cards.
We need to determine the probability of getting two queens and two kings.
<u>Probability of getting two queens and two kings:</u>
The number of ways of getting two queens is 
The number of ways of getting two kings is
Total number of cases is 
The probability of getting two queens and two kings is given by
Substituting the values, we get;
Simplifying, we get;
Thus, the probability of getting two queens and two kings is 0.000133
Use a system of equations:
For his trip on the way there:
D = 7*s
For his trip on the way home you have:
D = 5*(s+18)
use substitution to solve
The answer would be letter D!
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Answer:
Step-by-step explanation:
Start with h(t) = -16t^2 + initial height, which here is h(t) = -16t^2 + 1296. Set this = to zero, which corresponds to the object hitting the ground (h = 0):
0 = -16t^2 + 1296. Dividing all terms by -16, we get t^2 = 81, whose positive square root is 9. It takes 9 seconds for the object to hit the ground.
