In both problems, the sum of side lengths is the perimeter. Opposite sides of a parallelogram (or rectangle) are equal in length, so you can find the perimeter by doubling the sum of adjacent sides.
25. 2(x +(x +15)) = (x +45) +(x +40) +(x +25)
.. 4x +30 = 3x +110 . . . . . . . . . . . . . . . . . . . . . . simplify
.. x = 80 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . subtract 3x+30
.. 4x +30 = 4*80 +30 = 240
The perimeter of each is 240 units.
26. 2(x +(x +2)) = (x) +(x +6) +(x +4)
.. 4x +4 = 3x +10 . . . . . . . . . . . . . . . . . . . . . . simplify
.. x = 6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . subtract 3x+4
.. 4x +4 = 4*6 +4 = 28
The perimeter of each is 28 units.
Answer:
-1
Step-by-step explanation:
The given equation has a y-intercept of 8, so goes through the point (0, 8).
If the line also goes through the point (2, 6) it has a slope of ...
(y2 -y1)/(x2 -x1) = (6 -8)/(2 -0) = -2/2 = -1
The slope of the line is -1.
_____
The value of A is -2.
<h3>
Answer:</h3>
a. -(3√13)/13
<h3>
Step-by-step explanation:</h3>
The cosine can be found from the tangent by way of the secant.
tan(θ)² +1 = sec(θ)² = 1/cos(θ)²
Then ...
cos(θ) = ±1/√(tan(θ)² +1)
The <em>cosine is negative in the second quadrant</em>, so we will choose that sign.
cos(θ) = -1/√((-2/3)² +1) = -1/√(4/9 +1) = -1/√(13/9)
cos(θ) = -3/√13 = -(3√13)/13 . . . . . matches your selection A
Answer:
(x + n)^2
Step-by-step explanation:
Okay! Let's get this going!
(x + n ) ^2 is correct because first we get
x^2 and n^2. Yet we need to add one more part to this to make it true which is x * n. We multiply this by two since according to the formula (a + b)^2 = a^2 + 2ab + b^2
:)
Answer:
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