Question

Q10 Please help me solve this….

Answer 1

Answer:

C. 0.23°

Step-by-step explanation:

We are given

$r=\frac{1}{32}v^{2}sin(2\theta)$

Re-arranging this equation (multiply by 32 on both sides and divide by $v^{2}$ on both sides gives us:

$\frac{32r}{v^{2}}=sin(2\theta)$ or

$sin(2\theta)=\frac{32r}{v^{2}}$

Substituting for, r and v we get

$sin(2\theta)=\frac{(32)5000}{4500^{2}}=0.00792\\\\\theta=sin^{-1}(0.0079)=0.4527\\\\\theta=\frac{{0.4527}}{2}=0.2263\approx0.23$