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Mrrafil [7]
2 years ago
13

Q10 Please help me solve this….

Mathematics
1 answer:
kondor19780726 [428]2 years ago
5 0

Answer:

C. 0.23°

Step-by-step explanation:

We are given

r=\frac{1}{32}v^{2}sin(2\theta)

Re-arranging this equation (multiply by 32 on both sides and divide by v^{2} on both sides gives us:

\frac{32r}{v^{2}}=sin(2\theta) or

sin(2\theta)=\frac{32r}{v^{2}}

Substituting for, r and v we get

sin(2\theta)=\frac{(32)5000}{4500^{2}}=0.00792\\\\\theta=sin^{-1}(0.0079)=0.4527\\\\\theta=\frac{{0.4527}}{2}=0.2263\approx0.23

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Leno4ka [110]

Answer:

  1. (-0.0008)^0 =1
  2. 1291^1 =1
  3. (1/3)^0 = 1

Step-by-step explanation:

\mathrm{Apply\:exponent\:rule}:\quad \:a^0=1,\:\\\\(-0.0008)^0 = 1\\\\1291^0 =1\\\\-(-3141)^0 = -1\\\\-(\frac{5}{8} )^0 =-1\\\\0^1 = 0\\\\(\frac{1}{3} )^0 = 1\\

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3 years ago
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ELEN [110]
Yeah I think x=12y on this one correct me if I’m wrong
3 0
3 years ago
What is the area underneath a normal curve always equal to?
Pani-rosa [81]
The correct answer is C. One
3 0
3 years ago
Read 2 more answers
A 3 kg toy car rests st the top of a 0.45 meter ramp. What is its gravitational potential energy?
salantis [7]
<span>gravitational potential energy : P
Gravity : g
Mass : m
height : h

P = mgh  = 3 x 9.8 x 0.45 = 13.23 Joule

Potential energy is work , from the known formula

W = Fd ( work = force x distance ) 

W = P ( in case of potential energy height change)

F is the force acting on the body in case of ideal ramp , the only force acting is the weight of the body

F = mg ( not just <m> as the force is mg (Newton) gravity effect)

d is the displacement in direction of force, as we have considered the force to be the weight not it's component in direction of the ramp , the change in displacement is the change in height so

d = h 

W = Fd = (F = mg) x (d = h) = mgh 

W = mgh = P


</span>

7 0
3 years ago
P + 12 = 30<br> Solve the equation .
yuradex [85]

Answer:

p=18

Step-by-step explanation:

p+12=30

subtract 12 from each side

p=18

8 0
3 years ago
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