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sladkih [1.3K]
3 years ago
8

Can someone help with this please?

Mathematics
1 answer:
UNO [17]3 years ago
7 0

Step-by-step explanation:

for 1

x = 11 using tan

y = 22 using sin

for no 2

x= 16 using cos

y= 16root 3 using sin

I believe with this u can do the others

have fun....

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Which is the correct answer?
dlinn [17]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
NEED HELP FAST‼️‼️
ch4aika [34]

Answer:

Step-by-step explanation:

A ' = (-2, -3)

B ' = (0, -3)

C ' = (-1, 1)

=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as

Applying this rule to the three given points will mean....

Point A = (-2, 3) becomes A ' = (-2, -3)

Point B = (0, 3) becomes B ' = (0, -3)

Point C = (-1, -1) becomes C ' = (-1, 1)

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.

4 0
3 years ago
Use the zero product property to find the solutions to the equation x2 – 13x + 30 = 0.
alukav5142 [94]

Answer:

<u>The solutions to this quadratic equation are 10 and 3.</u>

Step-by-step explanation:

1. Let's recall the formula for solving this type of equations, called quadratic equations:

 x = ( - b +/- √ b² - 4ac)/ 2a

The equation given is  x2 – 13x + 30 = 0,

where a = 1, b = - 13 and c = 30

Now replacing with the real values, we have

x = [ - (-13) +/- √ (-13)² - 4 * 1 * 30] / 2 * 1

x = [ 13 +/- √ 169 - 120] / 2

x = [13 +/- √ 49]/ 2

x = [ 13 +/- 7 ]/ 2

<u>x₁ = 13 + 7/2 = 20/2 = 10</u>

<u>x₂ = 13 - 7/2 = 6/2 = 3</u>

8 0
3 years ago
PWEASE HELP, AREA OF A TRAPEZOID
sdas [7]

Answer:

34 m²

Step-by-step explanation:

4 0
2 years ago
X + 4 is prime x2 – 9 can be factored using the formula.
Anna71 [15]

We are given two binomials: x+4 , x^2-9.

x+4 can't be factored. Therefore,  it is a prime.

Let us work on x^2-9.

9 could be written as 3^2.

Therefore, x^2-9 = x^2 - 3^2.

Now, we can apply difference of the squares formula to factor it.

We know a^2 -b^2 = (a-b) (a+b).

Therefore,  x^2 - 3^2 can be factored as (x-3) (x+3).

So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).

3 0
3 years ago
Read 2 more answers
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