angles EFH and GFH are congruents
for the second equivalence criterion two triangles are equivalents if they have respectively 2 angles and 1 side congruents
the two triangles have congruents the angle right angle (HGF and HEF) and the 55 degrees angles (EFH and GFH); then they have in common the HF side.
so the triangles are congruent and so all the sides are respectively congruent,for example EH with HG:
EH=HG
s+36=7s
s+36-7s=0
s-7s=-36
-6s=-36
6s=36
s=6
<em>sorry for my english</em>
Invert and multiply
2/x*(3/(4x))
Then proceed to simplify
(You must simplify twice might I add)
The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
Answer:
I'm in eight grade so don't assume i'm right. But from looking at this. It looks like x-1=8 and y+1= 28. I'm only doing High School Math 1 in eight grade tho. So if i'm wrong i'm sorry
Step-by-step explanation:
