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Luda [366]
2 years ago
14

Give the standard form for 7000+300+40+2

Mathematics
2 answers:
PtichkaEL [24]2 years ago
7 0

Answer:

7×10³+3×10²+4×10¹+2×10 or 7.342×10³

Tatiana [17]2 years ago
4 0
Hello there! The standard form of 7,000 + 300 + 40 + 2 would be 7,342. To explain, we can start by defining place values and identifying why the standard form is 7,342.

What are place values?

Place values are representative digit placeholders of numbers that, when adding a 0 behind them, can show a true value. In this problem, four place values are used to show the expanded variant of 7,342. We know this is the standard form because there are four digits that are to the left of the decimal point; 7 is in the thousands place, which as a number converts to 7 x 1,000. When multiplying 7 by 1,000, we will find that we receive 7,000. Because the thousands place is four digits to the left of the decimal point and can only be a placeholder for one number at a time, we say that 7 represents this number’s thousands digit. 3 is in the hundreds place, meaning that we can find its value through multiplication of 3 by 100. 3 x 100 is 300, and we can use 3 as the representative of the hundreds place. The same rule applies for 4; it is in the hundreds place and can be verified by multiplying 4 by 10. 4 x 10 is 40, and we can leave the 4 out because it is the only value other than 0. And lastly, there is 2. 2 is in the ones place, and it can be left alone because anything multiplied by one equals the number that was multiplied by one. Given this multiplication rule, 2 x 1 = 2. We can leave 2 alone. Adding 7,000, 300, 40, and 2 gives us 7,342 as our total. If you need any extra help, let me know and I will gladly assist you.
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Answer:

Part 7) Adjacent angles

m<SUR and m<RUN

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m<SUR and m<PUQ

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Part 10) m

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Part 13) m

Step-by-step explanation:

Part 7) we know that

we know that

Two angles are Adjacent when they have a common side and a common vertex

In this problem

m<SUR and m<RUN ----> are adjacent angles

because have a common side UR and a common vertex U

m<TUP and m<PUQ ----> are adjacent angles

because have a common side UP and a common vertex U

Part 8) we know that

An angle is acute when is measure is less than 90 degrees

Vertical Angles are the pair of congruent angles opposite each other when two lines cross

In this problem

m ------> by vertical angles

m ------> by vertical angles

Part 9) we know that

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In this problem

m ------> by supplementary angles

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Part 10) Find m<QUR

we know that

m ------> by supplementary angles

we have

m

substitute

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we know that

m<TUR=m<TUS+m<SUR

substitute the values

m

m ----> see the procedure problem 10

therefore

m<RUQ is greater than m< TUR

Part 12) Find the measure angle x

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solve for x

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Part 13) m<KMH

we know that

m -----> by supplementary angles

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