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Advocard [28]
3 years ago
10

Show all the work to multiply (3+V-16)(6-v-64)

Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0
=18-3v-192-6v-v^2-64v-96+16v+1024
=-v^2-57v+754
=-(v^2+45v-754)
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Which statements about the two landscaping companies is true?
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I think it would be all of them 

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Find the lengths of each side. Label with numbers. WILL GIVE BRAINLIEST​
choli [55]

Answer:

2 x + 6 . 8 = 8 x + I . 4

8x _2x = 6.8 - 1.4

6x = 5.4

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3 years ago
If h(x) = 5x – 3 and j(x) = -2x, solve h[j(2)]
Yuki888 [10]

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-23

Step-by-step explanation:

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3 years ago
What is the midpoint of the segment shown below? (-2, 3) (10, 3)
sergeinik [125]

Answer:

That point P(x,y)

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5 0
3 years ago
In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform
Semmy [17]

Answer:

95% Confidence interval:  (0.0429,0.0791)      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

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\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)

is the required confidence interval for proportion of all new websites that were anonymous.

8 0
3 years ago
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